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MakcuM [25]
3 years ago
15

In which of these situations would the answer to the question be 0

Mathematics
1 answer:
Jlenok [28]3 years ago
8 0
Post the situations maybe?
You might be interested in
find the area and perimeter of a rectangle with a width of 2 1/3inch and a length of 5 2/5inches. show your work please.
aleksandrvk [35]
Area: If you multiply 2 1/3 by 5 2/5, you get an answer of about: 12.6, which means the area is about: 12.6in. squared.
Perimeter: If you add 2 1/3+ 2 1/3+ 5 2/5+ 5 2/5 you get an answer of about: 15.47. So, the perimeter is about 15.47in.

Note: If you aren't allowed to use a calculator on this test, you should probably multiply the numbers yourself so you get show the work and get the answer in a fraction, which is probably what they want. If you are allowed to use calculators, all the information you need is right here.
4 0
3 years ago
Read 2 more answers
This math my graduation depends on it
In-s [12.5K]

In an arithmetic sequence, consecutive terms have a fixed distance d between them. If a₁ is the first term, then

2nd term = a₂ = a₁ + d

3rd term = a₃ = a₂ + d = a₁ + 2d

4th term = a₄ = a₃ + d = a₁ + 3d

and so on, up to

nth term = a_n = a_{n-1} + d = a_{n-2} + 2d = a_{n-3} + 3d = \cdots = a_1 + (n-1)d

so that every term in the sequence can be expressed in terms of a₁ and d.

6. It's kind of hard to tell, but it looks like you're given a₁₃ = -53 and a₃₅ = -163.

We have

a₁₃ = a₁ + 12d = -53

a₃₅ = a₁ + 34d = -163

Solve for a₁ and d. Eliminating a₁ and solving for d gives

(a₁ + 12d) - (a₁ + 34d) = -53 - (-163)

-22d = 110

d = -5

and solving for a₁, we get

a₁ + 12•(-5) = -53

a₁ - 60 = -53

a₁ = 7

Then the nth term is recursively given by

a_n = a_{n-1}-5

and explicitly by

a_n = 7 + (n-1)(-5) = 12 - 5n

7. We do the same thing here. Use the known terms to find a₁ and d :

a₁₉ = a₁ + 18d = 15

a₃₈ = a₁ + 37d = 72

⇒   (a₁ + 18d) - (a₁ + 37d) = 15 - 72

⇒   -19d = -57

⇒   d = 3

⇒   a₁ + 18•3 = 15

⇒   a₁ = -39

Then the nth term is recursively obtained by

a_n = a_{n-1}+3

and explicitly by

a_n = -39 + (n-1)\cdot3 = 3n-42

8. I won't both reproducing the info I included in my answer to your other question about geometric sequences.

We're given that the 1st term is 3 and the 2nd term is 12, so the ratio is r = 12/3 = 4.

Then the next three terms in the sequence are

192 • 4 = 768

768 • 4 = 3072

3072 • 4 = 12,288

The recursive rule with a₁ = 3 and r = 4 is

a_n = 4a_{n-1}

and the explicit rule would be

a_n = 3\cdot4^{n-1}

7 0
2 years ago
WILL GET BRANLIEST
erma4kov [3.2K]

Answer:

The correct options are;

Answer to A1 is D

Answer to A2 is D

Answer to A3 is D

Answer to A4 is D

Answer to A5 is D

Answer to A6 is D

Answer to A7 is D

Answer to A8 is D

Answer to A9 is D

Answer to B1 is I

Answer to B2 is I

Answer to B3 is I

Answer to B4 is I

Answer to B5 is I

Answer to B6 is I

Step-by-step explanation:

The given function is f(x) = 9·x² + 54·x - 66

The extremum of the function are found as follows;

d(f(x))/dx = 0 = d(9·x² + 54·x - 66)/dx = 18·x + 54

∴ 18·x + 54 = 0 at the maximum or minimum points

x = -54/18 = -3

Given that d²(f(x))/dx² = 18 > 0. x = -3 is a minimum point

Given that the function is a quadratic function, we have;

1) Points to the left of x = -3 are decreasing

2) Points to the right of x = -3 are increasing.

6 0
3 years ago
Bacteria colonies increase by 37% every 2 days. If you start with 55 microorganisms, how large would the colony be after 10 days
ahrayia [7]

The number of microorganisms that I will have after 10 days would be: 245.41 microoganisms.

<h3>How to calculate the number of microorganisms that I will have after 10 days?</h3>

To calculate the number of microorganisms that I will have after 10 days, I must perform the following operations:

We need to find 37% of 55 as shown below:

  • 55 ÷ 100 = 0.55
  • 0.55 x 37% = 20.35
  • 55 + 20.35 = 75.35

So after 2 days I will have 75.35 microorganisms.

  • 75.35 ÷ 100 = 0.75
  • 0.7535 x 37% = 27.87
  • 75.35 + 27.87 = 103.22

On the fourth day I will have: 103.22 microorganisms.

  • 103.22 ÷ 100 = 1.0322
  • 1.0322 x 37% = 38.19
  • 103.22 + 38.19 = 141.41

On the sixth day I will have 141.41 microorganisms.

  • 141.41 ÷ 100 = 1.4141
  • 1.4141 x 37% = 52.32
  • 141.41 + 52.32 = 193,73

On the eighth day I will have 193.73 microorganisms.

  • 193.73 ÷ 100 = 1.9373
  • 1.9373 x 37% = 71.68
  • 193.73 + 71.68 = 265.41

On the tenth day I will have 245.41 microoganisms.

Learn more about percentages in: brainly.com/question/13450942

#SPJ1

3 0
2 years ago
John and 2 friends are going out for pizza for lunch. They split one pizza and 3 large drinks. The pizza cost $14.00. After usin
MariettaO [177]

Answer:

$2.55

Step-by-step explanation:

2d + $14.00 – $7.00 = $12.10; $2.55

6 0
2 years ago
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