could someone please help answer this, thank you, please no spam, will give brainliest, (homework help)!

Police plan to enforce speed limits by using radar traps at four different locations within the city limits. The radar traps at

dalvyx [7]

Answer:

The probability that the person gets a speeding ticket is 0.27

Step-by-step explanation:

The probability that the person receives a speeding ticket is the probability that the person passes through any of the speed limits and the radar is operating at that time.

Let $P(L_1)$ is the probability that the person passes through radar $L_{1}$ and it is operating at that time is

$P(L_{1})=P(1)\times P(2)$

Where

P(1) is the probability of person passes through $L_{1}$

P(2) is probability that the radar is operating

$P(L_1)=0.2\times 0.4=0.08$

Similarly the probabilities are calculated for other radars in the similar manner as

$P(L_2)=0.1\times 0.3=0.03$

$P(L_3)=0.5\times 0.2=0.1$

$P(L_4)=0.2\times 0.3=0.06$

Thus the reuired probability of the reuired event is

$P(E)=P(L_1)+P(L_2)+P(L_3)+P(L_4)\\\\P(E)=0.08+0.03+0.1+0.06=0.27$

8 0

2 years ago

Which whole numbers fall betweeen .53 and 2.5

Aloiza [94]

Whole numbers are 0,1,2,3 etc. so it would be 1 and 2

6 0

2 years ago

If g(x) = a f(x + b), how is f(x) transformed to get g(x)?

nevsk [136]

Answer:

There was a Horizontal translation left b units and then Vertical stretch or compression

Step-by-step explanation:

Given : $g(x) = a f(x + b)$

We are supposed to show the transformation

Rule : f(x)→f(x+c)

Horizontal translation left c units

So, f(x+b) is the Horizontal translation left b units

Rule : f(x)→cf(x)

Vertical stretch or compression

So, $g(x) = a f(x + b)$

So, Initially there was a Horizontal translation left b units and then Vertical stretch or compression

5 0

3 years ago

Whats the sum of Radical 18 and Radical 72?

Romashka [77]

Https://www.wyzant.com/resources/answers/46749/the_sum_of_radical_18_and_radical_72_is

4 0

2 years ago

Assume that adults have IQ scores that are normally distributed with a mean of mu equals 105 and a standard deviation sigma equa

Sindrei [870]

Answer:

0.7698

Step-by-step explanation:

If you call your random variable $X$ , then what you are looking for is

$P(87 \leq X \leq 123)$

because you want the probability of $X$ being <em>between 87 and 123.</em>

We need a table with of the normal distribution. But we can only find the table with $\mu = 0$ and $\sigma = 1$ . Because of that, first we need to <em>normalize </em>our random variable:

$Z = \frac{X - \mu}{\sigma} = \frac{X - 105}{15}$

(you can always normalize your variable following the same formula!)

now we can do something similar to our limits, to get a better expression:

$\frac{87 - 105}{15} = \frac{-18}{15} = -1.2$

$\frac{123 - 105}{15} = \frac{18}{15} = 1.2$

And we transform our problem to a simpler one:

$P(87 \leq X \leq 123) = P(-1.2 \leq Z \leq 1.2) = P(Z \leq 1.2) - P(Z \leq -1.2)$

(see Figure 1)

From our table we can see that $P(Z \leq 1.2) = 0.8849$ (this is represented in figure 2).

Remember that the whole area below the curve is exactly 1. So we can conclude that $P(Z \geq 1.2) = 0.1151$ (because 0.8849 + 0.1151 = 1). We also know the normal distribution is symmetric, then

$P(Z \leq -1.2)= P(Z \geq 1.2) = 0.1151$ .

FINALLY:

$P(Z \leq 1.2) - P(Z \leq -1.2) = 0.8849 - 0.1151 = 0.7698$

5 0

3 years ago