Answer:
A.20per ton
B.141,600
C.389,400
Explanation:
A.
($856,800+$97,200-$108,000+$216,000)/53,100 tons
=$1,062,000/53,100
= 20per ton
(b)
Resources removed totaled 26,550 tons
Less company sold 19,470 tons.
Balance 7,080 tons
Hence
Inventory 20*7,080
=141,600
(c)
20* 19,470 tons
=389,400
Answer:
9.37
Explanation:
The computation of LCL for a control chart is shown below:-
Sample Obs 1 Obs 2 Obs 3 Obs 4 Mean observation Range
1 10 12 12 14 12 4
2 12 11 13 16 13 5
3 11 13 14 14 13 3
4 11 10 7 8 9 4
5 13 12 14 13 13 2
For computing the mean observation and range we will use the below formulas
Mean observation = ( Obs 1 + Obs 2 + Obs 3 + Obs 4) ÷ 4
Range = Highest value - Lowest value
= ( 12 + 13 + 13 + 9 + 13 ) ÷ 5
= 12
= ( 4 + 5 + 3 + 4 + 2 ) ÷ 5
= 3.6
Since we found the value of A2 with the help of constants table for control charts for a 4 subgroup size.
A2 = 0.729
12 - 0.729 × 3.6
= 9.37
Answer:
The correct answer is the option A: a person with a high opportunity cost of time.
Explanation:
To begin with, the opportunity cost of something is what the person sacrificies in order to be doing that thing. Therefore that when we talk about the opportunity cost of time it refers to what the person sacrificies in order to do something with that time. If the person has a high opportunity cost of time then the sacrificies that he made with that time will be higher than other person that has a low opportunity cost of time, meaning that the time spent by that person is less important than to the one that has a lot of time to spare.
Answer:
I don't know
Explanation:
Prepare a narrated PowerPoint presentation that will highlight the following items.
a. Your calculations for the amount of property, plant, and equipment and the annual depreciation for the project
b. Your calculations that convert the project's EBIT to free cash flow for the 12 years of the project.
c. The following capital budgeting results for the project:
1. Net present value
2. Internal rate of return
3. Discounted payback period.
Answer:
Standard deviation = 47.69% (Approx)
Explanation:
Given:
Portfolio of Apple stock w1 = 25% = 0.25
Portfolio of Tesla stock w2 = 75% = 0.75
Standard deviation return Apple σ1 = 35% = 0.35
Standard deviation return Tesla σ2 = 60% = 0.60
Correlation coefficient ρ12 = 0.22
Find:
Standard deviation
Computation:
Standard deviation = √w1²σ1² + w2²σ2² + 2w1σ1w2σ2ρ12
Standard deviation = 0.4769
Standard deviation = 47.69% (Approx)
