12 red markers to 12 blue markers

Ramon earns $1,880 each month and pays $53.30 on electricity. To the nearest tenth of a percent, what percent of Ramon's earning

AfilCa [17]

<h2>Answer:</h2>

Each month, 2.8% Ramon's earnings are spent on electricity.

<h2>Step-by-step explanation:</h2>

You know, that 100 percent are his earnings - $1,880

Now, you need to find out, how much is 1%. You do that by dividing $1,880 by 100.

Now you have to divide the amount he pays on electricity - $53.3 by one percent of his earnings - $18.8

So, now you know, that he pays exactly 2.83511% of his earnings on electricity. But from assignment, you know, that it has to be rounded to the nearest tenth of a percent. The number is 2.8351. So we will round it to 2.8% ,because 3 is rounded down. (https://www.mathsisfun.com/rounding-numbers.html)

100% = $1,880

$1,880/100 = $18.8

$53.3/$18.8 = 2.83511

2.83511% ≈ 2.8%

3 0

2 years ago

Differentiating a Logarithmic Function In Exercise, find the derivative of the function.

sp2606 [1]

Answer:

$\dfrac{d(f(x))}{dx} = \dfrac{2}{x}$

Step-by-step explanation:

We are given the following function in the question:

$f(x) = \ln (3x^2)$

We have to derivate the given function.

Formula:

$\dfrac{d(\ln x)}{dx} = \dfrac{1}{x}\\\\\dfrac{d(x^n)}{dx} = nx^{n-1}$

The derivation takes place in the following manner

$f(x) = \ln (3x^2)\\\\\dfrac{d(f(x))}{dx} = \displaystyle\frac{d(\ln(3x^2))}{dx}\\\\=\frac{1}{3x^2}\times \frac{d(3x^2)}{dx}\\\\= \frac{1}{3x^2}\times (6x)\\\\=\frac{6x}{3x^2}\\\\=\frac{2}{x}$

$\dfrac{d(f(x))}{dx} = \dfrac{2}{x}$

5 0

2 years ago

Trig: A sector of a circle has area 25 cm2 and centralangle

Alchen [17]

Answer: Radius = 10 cm and Arc length = 5 cm

Step-by-step explanation:

The area of a sector with radius r and central angle $\theta$ (In radian) is given by :-

$A=\dfrac{1}{2}r^2\theta$

Given : A sector of a circle has area $25 cm^2$ and central angle 0.5 radians.

Let r be the radius , then we have

$25=\dfrac{1}{2}r^2(0.5)\\\\\Rightarrow\ r^2=\dfrac{2\times25}{0.5}\\\\\Rightarrow\ r^2=\dfrac{50}{0.5}=100\\\\\Rightarrow\ r=\sqrt{100}=10\ cm$

Thus, radius = 10 cm

The length of arc is given by :-

$l=r\theta=10\times0.5=5\ cm$

Hence, the length of the arc = 5 cm

3 0

2 years ago

An amount a divided by 17

Ad libitum [116K]

What’s the question for it?

8 0

2 years ago

Use DeMorgan's laws to write a negation for the statement "the Hulk is green or the Iron Man is red"

erastova [34]

Answer:

"The Hulk is not green AND the Iron Man is not red"

Step-by-step explanation:

DeMorgan's laws state that the negation of an statement whose structure is "p OR q" is "not p AND not q", and similarly, that the negation of an statement whose structure is "p AND q" is "not p OR not q". The statement we want to negate in our case is "The Hulk is green OR the Iron Man is red". This is an statement whose structure is of the type "p OR q", where p would be "The Hulk is green", and q would be "the Iron Man is red". So according to DeMorgan's laws, its negation should be the statement "not p AND not q". To put them in common english, not p would be "The Hulk is NOT green", and not q would be "The Iron Man is NOT red". So the statement "not p AND not q" is simply "The Hulk is not green AND the Iron Man is not red".

7 0

3 years ago