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3 years ago

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The radius of the Moon is 1700 km, and the radius of the Earth is 6350 km. A scale model of the Earth and the Moon is made. In t

he model, the radius of the Moon is 3.4 cm. (i) Find the radius of the scale model of the Earth. (ii) Find the volume of the scale model of the Earth.

1 answer:

Reil [10]3 years ago

3 0

Answer:

1) 12.7 cm

2) 8580.24 cm³

Step-by-step explanation:

given,

Radius of moon(Rm) = 1700 Km Radius of Earth(Re) = 6350 km

Model radius of Moon(Mm) = 3.4 cm

2) Volume of earth model = $\dfrac{(R_e)^3}{(R_m)^3}\times \dfrac{4}{3}\pi (M_m)^3$

= $\dfrac{(6350)^3}{(1700)^3}\times \dfrac{4}{3}\pi (3.4)^3$

= 8580.24 cm³

1) radius of earth = $\dfrac{R_e}{R_m}\times M_m$

= $\dfrac{6350}{1700}\times 3.4$

= 12.7 cm

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Given the event "a die lands with a 6 on top", which of the following is the complement of this event? Choose the correct ans

Veronika [31]

Answer:

The die lands with a 1, 2, 3, 4, or 5 on top ⇒ answer D

Step-by-step explanation:

- Complementary events are two outcomes of an event that are the

only two possible outcomes

- The Complement Rule states that the sum of the probabilities of

an event and its complement must equal 1

- P(A) + P(A') = 1

- Lets solve the problem

- The event A is:

" a die lands with a 6 on top "

∴ P(A) = $\frac{1}{6}$

∵ P(A) + P(A') = 1

∴ $\frac{1}{6}$ + P(A') = 1

- Subtract $\frac{1}{6}$ from both sides

∴ P(A') = $\frac{5}{6}$

∵ The die has six numbers from 1 to 6

∴ The other numbers than 6 are 1 , 2 , 3 , 4 and 5

∴ The complement of event A is:

" A die lands with 1 , 2 , 3 , 4 or 5 "

* The complement of the event is:

The die lands with a 1, 2, 3, 4, or 5 on top

8 0

3 years ago

Giving brainiest+points need explanation on this one my answer is 25 is it right?

natka813 [3]

Known facts:
A line shaft rotating at 250 rpm, a grinder shaft that turns at 1200 rpm diameter of grinder pulley is 5 inches.

1. Proportion equation
350/1200 = 5/x

2. Cross multiply
1200*5=250*x
x=(1200*5)/250 = (24*50*5)/(5*50) = 24
The big wheel diameter is 24 inches

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3 years ago

Need answer 25 and answer 27

UNO [17]

$\\ \bull\tt\dashrightarrow \dfrac{-3}{8}x-20+2x>6$

$\\ \bull\tt\dashrightarrow \dfrac{-3}{8}x+2x=6+20=26$

$\\ \bull\tt\dashrightarrow \dfrac{-3+16}{8}x=26$

$\\ \bull\tt\dashrightarrow \dfrac{13}{8}x=26$

$\\ \bull\tt\dashrightarrow x=26\times \dfrac{8}{13}$

$\\ \bull\tt\dashrightarrow x=8(2)=16$

#27

$\\ \bull\tt\dashrightarrow 0.5x-4-2x\leqslant 2$

$\\ \bull\tt\dashrightarrow 0.5x-2x\leqslant=2+4=6$

$\\ \bull\tt\dashrightarrow -1.5x\leqslant 6$

$\\ \bull\tt\dashrightarrow x\leqslant\dfrac{6}{-1.5}$

$\\ \bull\tt\dashrightarrow x\leqslant 4$

8 0

3 years ago

X^2 - y^2 = 100

luda_lava [24]

Answer:

20

Step-by-step explanation:

Let's start by rewriting the second equation in terms of "x":

$x+y=5$

Subtract y from both sides:

$x=5-y$

Now, substitute "5-y" for "x" in the first equation:

$(5-y)^2-y^2=100$

Note that:

$(a-b)^2=a^2-2ab+b^2$

$25-10y+y^2-y^2=100$

Cancel out like terms:

$25-10y=100$

Subtract 25 from both sides:

$-10y=75$

Divide both sides by -10

$y=\frac{75}{-10}=\frac{15}{-2}=-\frac{15}{2}$

Now, substitute this value back into either of the equations to solve for x.

$x+y=5\\x-\frac{15}{2}=5\\$

Add 15/2 to both sides:

$x=5+\frac{15}{2}\\x=\frac{10}{2}+\frac{15}{2}\\x=\frac{25}{2}$

Now, find the difference:

$x-y=\frac{25}{2}-(-\frac{15}{2})=\frac{25}{2}+\frac{15}{2}=\frac{40}{2}=20$

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2 years ago

Please help me i am desperate please (1/3)

Sergeu [11.5K]

I think we're not supposed to do more than 3 problems in one answer; certainly not five pages. Does the 1/3 mean there are 10 more to come?

I'll do the first page.

6)

Right triangle, opposite side of 10, adjacent side of 21,

tan x = opp/adj = 10/21

x = arctan 10/21 = 25.46°

Answer: 25

7)

cos x = adj / hyp = 10/14

x = arccos 10/14 = 44.42°

Answer: 44

8)

tan x = opp/adj = 12/24 = 1/2

x = arctan 1/2 = 26.57°

Answer: 27

9)

tan x = 31/32

x = arctan 31/32 = 44.09°

Answer: 44

10)

x = arctan 10/27 = 20.32°

Answer: 20

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3 years ago