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Sedbober [7]
3 years ago
5

How do you round the numbers 33 and 89 to estimate there sum

Mathematics
1 answer:
Arturiano [62]3 years ago
5 0

You'd round 33 to the nearest ten which is 30 and 89 to the nearest ten which is 90. And the sum? well, 30+90=120! I hope this helps!

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(4×⁴+3׳+2ײ-×+1)+(5ײ-2×+3)​
Annette [7]

Answer:

4×⁴+3׳+7ײ-3x+4

Step-by-step explanation:

First remove the parentheses and pair up like terms

4×⁴+3׳+2ײ+5ײ-x-2x+1+3

Then combine the like terms

4×⁴+3׳+7ײ-3x+4

Which is the answer.

3 0
3 years ago
The school orchestra has 25 woodwinds, 20 percussionists, 15 strings and 40 brass instruments.
tankabanditka [31]

Answer: select all what that apply?

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
Consider the hypothesis test below.
Pavel [41]

Answer:

Z_{H0} =1.79

p-value: 0.0367

Decision: Reject H₀

Step-by-step explanation:

Hello!

Hypothesis to test:

H₀:ρ₁-ρ₂=0

H₁:ρ₁-ρ₂>0

The statistic to use to test the difference between two population proportions is the approximation of Z

Z=<u>     (^ρ₁-^ρ₂)-(ρ₁-ρ₂)     </u>   ≈N(0;1)

   √ (<u>^ρ₁(1-^ρ₁))/n₁)+(^ρ₂(1-^ρ₂)/n₂))</u>

                   

Z=<u>                    (0.28-0.15)-0                    </u>= 1.79

   √ (<u>0.28(1-0.28)/200)+(0.15(1-0.15)/300)</u>

p-value

Remember: The p-value is defined as the probability corresponding to the calculated statistic if possible under the null hypothesis (i.e. the probability of obtaining a value as extreme as the value of the statistic under the null hypothesis).

P(Z>1.79)= 0.0367

Conclusion:

Comparing the p-value against the significance level, you can decide to reject the null hypothesis.

I hope you have a SUPER day!

8 0
3 years ago
Little Snail is going to visit his friend over at the next pond, 3 miles away. He can crawl ( 1/2. 1/3, 1/4, 3/4, 2/3 ) of a mil
KIM [24]

Solution :

It is given that Little Snail is going to visit one of his friend at the pond which is 3 miles away.

When the snail crawls 1/2 of a mile per day, it will take him, $1 \times \frac{2}{1} \times 3$

   =  6 days to get to the next pond.

When the snail crawls 1/3 of a mile per day, it will take him, $1 \times \frac{3}{1} \times 3$

   =  9 days to get to the next pond.

When the snail crawls 1/4 of a mile per day, it will take him, $1 \times \frac{4}{1} \times 3$

   = 12 days to get to the next pond.

When the snail crawls 3/4 of a mile per day, it will take him, $1 \times \frac{4}{3} \times 3$

   =  4 days to get to the next pond.

When the snail crawls 2/3 of a mile per day, it will take him, $1 \times \frac{3}{2} \times 3$

   =  4.5 days to get to the next pond.

3 0
3 years ago
8(39 + 11)
Andrei [34K]

Answer:

option D is the correct answer

6 0
2 years ago
Read 2 more answers
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