Check the picture attached
let the rays forming angle T be ray 1 and ray 2
Draw a circle with center point T. Let the intersection of the circle with rays 1 and 2 be at points A and B respectively.
Draw 2 circles with centers A and <span>B so that:
The radii (radius'es) are equal, and they are large enough to intersect.
Denote the intersection of these 2 circles with C.
Join T to C. The line through T and C is the bisector.</span>
I think it’s A or D I think one of them
Add the last two equations to eliminate <em>x</em> :
(<em>x</em> - 2<em>y</em> - 3<em>z</em>) + (- <em>x</em> + <em>y</em> + 2<em>z</em>) = 0 + 3
- <em>y</em> - <em>z</em> = 3
<em>y</em> + <em>z</em> = -3
Subtract this from the first equation to eliminate <em>z</em>, then solve for <em>y</em> :
(2<em>y</em> + <em>z</em>) - (<em>y</em> + <em>z</em>) = -8 - (-3)
<em>y</em> = -5
Plug this into the first equation to solve for <em>z</em> :
2(-5) + <em>z</em> = -8
<em>z</em> = 2
Plug both of these into either the second or third equations to solve for <em>x</em> :
<em>x</em> - 2(-5) - 3(2) = 0
<em>x</em> = -4
I don’t understand either
Just cross multiply to find 18% of 430
18/100 = x/430
430 X 18 = 7740
7740 = 100x
7740/100 = 77.4
so Melcher took about 77 photos.