34 + 6.7t ≥ 60.8 subtract 34 from both sides
6.7t ≥ 26.8 divide by 6.7
t ≥ 4
they could rent it for 4 hours or less
Answer:
Step-by-step explanation:
You are given values for x. Plug them in to the given equations. Graph the two lines. Find the intersection. You can tell from the chart when you get the same y value for both equations
Answer:
y=x\\
x=y^{2} + 12y\\
y^{2} + 12y -x = 0\\
Delta = (12^{2}) - 4.1.(-x) = 144 +4X = 36.(4+x)
\sqrt{Delta} = 6 . \sqrt{(4+x)} \\
y' = \frac{-12 + 6.(\sqrt{(4+x)}}{2} = -6 + 3.\sqrt{(4+x)}\\
y" = -6 - 3.\sqrt{(4+x)}\\\\
y' = 3.\sqrt{(4+x)} - 6\\
y''= -3.\sqrt{(4+x)} - 6\\
Answer:
0
Step-by-step explanation:
Note that we start at (0, -4) and end at (7, -4). Thus, the net change in y over the interval [0, 7] is 0, and the average rate of change of f(x) over that interval is thus
0
--------- = 0
7
Answer:
-4x-5
Step-by-step explanation:
sorry I can't get the graph
