The average daily balance for the month was $84.21, and the finance charge for the month was $30.13.
<h3><u>Averages</u></h3>
Given that Sally's balance on her credit card is $75.00 on the first day of August, and she makes a payment of $18.00 on August 17 and a new purchase of $41.00 on August 29, and the annual interest rate is 21.25%, to determine what is Sally's average daily balance and finance charge for the month of August, the following calculation must be made:
- 75 x ((21.15/12 x 16) / 100) + 75 = A = 86.89
- 57 x ((21.15/12 x 13) / 100) + 57 = B = 70.06
- 98 x ((21.15/12 x 3) / 100) + 98 = C = 103.18
- (86.89 x 16 + 70.06 x 13 + 103.18 x 3) / 31 = X
- 84.21 = X
- 86.89 + 70.06 + 103.18 - 75 - 57 - 98 = Y
- 30.13 = Y
Therefore, the average daily balance for the month was $84.21, and the finance charge for the month was $30.13.
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Answer:
Step-by-step explanation:
The volume of a sphere can be determined by using the following formula:
(a) From the histogram, you can see that there are 2 students with scores between 50 and 60; 3 between 60 and 70; 7 between 70 and 80; 9 between 80 and 90; and 1 between 90 and 100. So there are a total of 2 + 3 + 7 + 9 + 1 = 22 students.
(b) This is entirely up to whoever constructed the histogram to begin with... It's ambiguous as to which of the groups contains students with a score of exactly 60 - are they placed in the 50-60 group, or in the 60-70 group?
On the other hand, if a student gets a score of 100, then they would certainly be put in the 90-100 group. So for the sake of consistency, you should probably assume that the groups are assigned as follows:
50 ≤ score ≤ 60 ==> 50-60
60 < score ≤ 70 ==> 60-70
70 < score ≤ 80 ==> 70-80
80 < score ≤ 90 ==> 80-90
90 < score ≤ 100 ==> 90-100
Then a student who scored a 60 should be added to the 50-60 category.
Answer:
x = 18 y = 10
Step-by-step explanation:
let the first number be x
let the second number be y
x = y + 8..... equation 1
2x + y = 46.... equation 2
x is the larger number
y is the smaller number.
Rearrange the equation and add equation 1 to equation 2.
x - y = 8
+ 2x + y = 46
-------------------
3x + 0 = 54
3x = 54
divide both sides by 3
x = 54/3
x = 18
Substitute x = 18 into equation 1
x = y + 8
18 = y + 8
collect like terms
y = 18-8
y = 10
