<u>Solution </u><u>1</u><u> </u><u>:</u><u>-</u>
Given expression ,
We know that,
Therefore , this can be written as ,
![\implies \sqrt[4]{13^3}](https://tex.z-dn.net/?f=%5Cimplies%20%5Csqrt%5B4%5D%7B13%5E3%7D%20)
<u>Solution</u><u> </u><u>2</u><u>:</u><u>-</u>
Given expression ,
We know that,
Therefore, this can be written as ,

Answer:
300. In this case, it's very easy to do this percentage inflation. Since 20 is a multiple of 100, and we want to know the 100%, you just multiply the 20 by 5 to make it 100. Along with this, you multiply the 60 by 5 as well, which gives you 300.
2/32 - 1/16 this is the probability (in fractions)
Correct Answer:Option A. 0.01
Solution:This is a problem of statistics and uses the concept of normal distributions. We need to convert the score of 90 into z-score and then find the desired probability from standard normal distribution table.
Converting 90 to z-score:

Now we are to find the probability of z score being more than 2.33. From the z-table the probability comes out to be 0.01.
Therefore, we can conclude that the probability of class average is greater than 90 is 0.01.
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Answer:
(t, u, w) = (1, -2, -2)
Step-by-step explanation:
A graphing calculator makes short work of this, giving the solution as ...
(t, u, w) = (1, -2, -2)
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There are many ways to solve this "by hand." Here's one of them.
Add the first and third equations. Their sum is ...
-3t +4w = -11 . . . . . [eq4]
Add this to twice the second equation. That sum is ...
(-3t +4w) +2(-4t -2w) = (-11) +2(0)
-11t = -11
t = 1
Substituting this into the second equation gives ...
-4(1) -2w = 0
w +2 = 0 . . . . divide by -2
w = -2 . . . . add -2
Substituting for t in the third equation lets us find u.
2(1) -2u = 6
-1 +u = -3 . . . . . divide by -2
u = -2 . . . . add 1
The solution is (t, u, w) = (1, -2, -2).