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svp [43]
3 years ago
15

Someone please tell me what to do

Mathematics
1 answer:
kifflom [539]3 years ago
4 0
For this, we need to find the area of the larger rectangle (The room) and subtract from that the area of the smaller, shaded rectangle (The rug).
A=LW (L=Length, W=Width, A=Area)

The larger rectangle first:
A=(15)(10)
A=150 feet squared

Now the Rug:
A=(12)(7)
A=84 feet squared

Now to find the area that is NOT covered by the rug, we subtract:
150-84
= 66 feet squared will NOT be covered by the rug.

Hope this Helps!
-Sinnamin
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3 A farmer has 580 square bales of hay in his shed with total mass 9850 kg.
rusak2 [61]

Answer:

a) 580 - 16n

b) 9850 - 271.72n

Step-by-step explanation:

a) starting number of bales = 580

each day, the farmer feeds out 2 bales of hay to each yard. he has 8 yards, so he feeds out 2 bales 8 times for a total of 2 * 8 = 16 bales. Therefore, he loses 16 bales each day

After the first day, he has 580-16 = 564 bales. After the second, he has 564-16 = 548 bales, and so on. He loses 16 bales n times for n days, and as a result, his final amount of bales is

original amount - amount lost = 580 - 16n

b)

First, we can calculate how much a bale weighs.

average = sum/count = 9850 kg / 580 ≈ 17 kg

Therefore, as he loses 16 bales of hay, he loses 17 kg 16 times, or approximately 271.72 kg of hay every day. For n days, he loses 271.72n kg. This brings his final amount to be

starting - amount lost = 9850 - 271.72n

4 0
3 years ago
What is a 4 digit number that can be divided by 5 and 9
Dahasolnce [82]
4410 is one of many numbers divisible by 5 and 9
8 0
3 years ago
What are the angles that make the trigonometric statements true?<br> Answer choices are ( A,B,C )
Firdavs [7]
Both answers are letter A. 
5 0
3 years ago
Read 2 more answers
For i≥1 , let Xi∼G1/2 be distributed Geometrically with parameter 1/2 . Define Yn=1n−−√∑i=1n(Xi−2) Approximate P(−1≤Yn≤2) with l
murzikaleks [220]

Answer:

The answer is "0.68".

Step-by-step explanation:

Given value:

X_i \sim \frac{G_1}{2}

E(X_i)=2 \\

Var (X_i)= \frac{1- \frac{1}{2}}{(\frac{1}{2})^2}\\

             = \frac{ \frac{2-1}{2}}{\frac{1}{4}}\\\\= \frac{ \frac{1}{2}}{\frac{1}{4}}\\\\= \frac{1}{2} \times \frac{4}{1}\\\\= \frac{4}{2}\\\\=2

Now we calculate the \bar X \sim N(2, \sqrt{\frac{2}{n}})\\

\to \frac{\bar X - 2}{\sqrt{\frac{2}{n}}}  \sim  N(0, 1)\\

\to \sum^n_{i=1}  \frac{X_i - 2}{n}  \times\sqrt{\frac{n}{2}}}  \sim  N(0, 1)\\\\\to  \sum^n_{i=1}  \frac{X_i - 2}{\sqrt{2n}}  \sim  N(0, 1)\\

\to Z_n = \frac{1}{\sqrt{n}} \sum^n_{i=1} (X_i -2) \sim N(0, 2)\\

\to P(-1 \leq X_n \leq 2)  = P(Z_n \leq Z) -P(Z_n \leq -1) \\\\

                               = 0.92 -0.24\\\\= 0.68

6 0
3 years ago
Reduce to simplest form. -\dfrac{1}{3}-\left(-\dfrac{3}{5}\right)=− 3 1 ​ −(− 5 3 ​ )=minus, start fraction, 1, divided by, 3, e
nevsk [136]

Answer:

-1/3 - (-3/5) = 4/15

Step-by-step explanation:

Reduce to simplest form

-1/3 - (-3/5)

= -1/3 + 3/5

Find the Lowest Common Multiple of 3 and 5

Lowest Common Multiple of 3and 5 is 15

Use the LCM to Simplify

= {(-5*1)+(3*3)} / 15

= (-5+9) / 15

= 4/15

Therefore,

-1/3 - (-3/5) = 4/15

7 0
3 years ago
Read 2 more answers
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