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Anna [14]
3 years ago
5

Vina has $4.70 in quarters, dimes and nickels in her purse. She has eight more dimes than quarters and six more nickels than qua

rters. How many of each coin does she have?
Mathematics
1 answer:
DanielleElmas [232]3 years ago
4 0

Nickels (0.05): Q + 6

Dimes (0.10): Q + 8

Quarters (0.25): Q

Nickels        +    Dimes      +  Quarters  = Total

0.05(Q + 6)  + 0.10(Q + 8) +   0.25(Q)    = 4.70

0.05Q + 0.30 + 0.10Q + 0.80 + 0.25Q = 4.70

                                         0.40Q + 1.10 = 4.70

                                                   0.40Q = 3.60

                                                            Q = 9

Nickels (0.05): Q + 6  = (9) + 6  = 15

Dimes (0.10): Q + 8   = (9) + 8   = 17

Answer: Nickels = 15, Dimes = 17, Quarters = 9

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Step-by-step explanation:

2a - 3b + 3a

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\large\boxed{x = 122^{o}}

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Read 2 more answers
Help based offf order of operations please help
JulijaS [17]

Answer:

The answer for :

h. \:  \:   \: \frac{5}{6}

i. \:  \:  \:  \frac{35}{32}

k. \:  \:  \:  \frac{-29}{20}

l. \:  \:  \:  \frac{13}{15}

Step-by-step explanation:

Question h:

\frac{2}{3}  + ( \frac{1}{3}  \times  \frac{1}{2} )

=  \frac{2}{3}  +  \frac{1}{6}

=  \frac{2 \times 2}{3 \times 2}  +  \frac{1}{6}

=  \frac{4}{6}  +  \frac{1}{6}

=  \frac{5}{6}

Question i:

\frac{7}{8}  +  \frac{1}{4}  \times ( \frac{3}{2}  -  \frac{5}{8} )

=  \frac{7}{8}  +  \frac{1}{4}  \times ( \frac{3 \times 4}{2 \times 4}  -  \frac{5}{8} )

= \frac{7}{8}  +  \frac{1}{4}  \times ( \frac{12}{8}  -  \frac{5}{8} )

=  \frac{7}{8}  +  (\frac{1}{4}  \times  \frac{7}{8} )

=  \frac{7}{8}  +  \frac{7}{32}

=  \frac{7  \times 4}{8 \times 4}  +  \frac{7}{32}

=  \frac{28}{32}  +  \frac{7}{32}

=  \frac{35}{32}

Question k:

\frac{3}{4}  - ( \frac{12}{7}  \div  \frac{12}{21} ) +  \frac{4}{5}

=  \frac{3}{4}  - ( \frac{12}{7}  \times  \frac{21}{12} ) +  \frac{4}{5}

=  \frac{3}{4}  -  \frac{3}{1}  +  \frac{4}{5}

= \frac{3 \times 5}{4 \times 5}  -  \frac{3 \times 20}{1 \times 20} +  \frac{4 \times 4}{5 \times 4}

=  \frac{15}{20}   -   \frac{60}{20} +  \frac{16}{20}

=  -  \frac{29}{20}

Question l:

\frac{5}{2}  \times ( \frac{2}{3}  -  \frac{1}{5} ) - ( \frac{2}{5}  \div  \frac{4}{3} )

=  \frac{5}{2}  \times ( \frac{2 \times 5}{3 \times 5}  -  \frac{1 \times 3}{5 \times 3} ) - ( \frac{2}{5}  \times  \frac{3}{4} )

=  \frac{5}{2}  \times ( \frac{10}{15}  -  \frac{3}{15} ) -  \frac{3}{10}

=  (\frac{5}{2} \times   \frac{7}{15}) -  \frac{3}{10}

=  \frac{7}{6}  -  \frac{3}{10}

=  \frac{7 \times 5}{6 \times 5}  -  \frac{3 \times 3}{10 \times 3}

=  \frac{35}{30}  -  \frac{9}{30}

=  \frac{26}{30}

=  \frac{13}{15}

8 0
3 years ago
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