Answer:
(7 x + 6 y)^2
Step-by-step explanation:
Factor the following:
49 x^2 + 84 x y + 36 y^2
The coefficient of x^2 is 49 and the coefficient of y^2 is 36. The product of 49 and 36 is 1764. The factors of 1764 which sum to 84 are 42 and 42. So 49 x^2 + 84 x y + 36 y^2 = 49 x^2 + 42 x y + 42 x y + 36 y^2 = 7 x (7 x + 6 y) + 6 y (7 x + 6 y):
7 x (7 x + 6 y) + 6 y (7 x + 6 y)
Factor 7 x + 6 y from 7 x (7 x + 6 y) + 6 y (7 x + 6 y):
(7 x + 6 y) (7 x + 6 y)
(7 x + 6 y) (7 x + 6 y) = (7 x + 6 y)^2:
Answer: (7 x + 6 y)^2
19) 15/a = 3/2
Start by cross multiplying....
3a = 30
Divide both sides 3
a = 10
21) 2/7 = 4/d
2d = 28
d= 14
23) 8/p = 3/10
80 = 3p
p = 26.66
25) 2 / -5 = 6/t
2t = -30
t = -15
The domain is the set of all possible values of independent variable I.e of x. The range is the complete set of all possible resulting values of the dependent variable of i.e of y
Answer:
I'm pretty sure it's 4 sorry if I'm not right I'm not the best at this stuff either
Answer:
Proportion of all bearings falls in the acceptable range = 0.9973 or 99.73% .
Step-by-step explanation:
We are given that the diameters have a normal distribution with a mean of 1.3 centimeters (cm) and a standard deviation of 0.01 cm i.e.;
Mean, 
= 1.3 cm and Standard deviation, 
= 0.01 cm
Also, since distribution is normal;
Z = 
~ N(0,1)
Let X = range of diameters
So, P(1.27 < X < 1.33) = P(X < 1.33) - P(X <=1.27)
P(X < 1.33) = P( < 
) = P(Z < 3) = 0.99865
P(X <= 1.27) = P( < 
) = P(Z < -3) = 1 - P(Z < 3) = 1 - 0.99865
= 0.00135
P(1.27 < X < 1.33) = 0.99865 - 0.00135 = 0.9973 .
Therefore, proportion of all bearings that falls in this acceptable range is 99.73% .
