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levacccp [35]
3 years ago
11

If the Pythagorean Theorem works for the triangle shown, which measurements would also work?

Mathematics
1 answer:
Natali5045456 [20]3 years ago
8 0
24,10,26. Basically if you multiply each of the sides by the same number, (I multiplied everything by 2) then that will keep the ratios the same. You should be able to multiply each side by any number, but two will usually be the easiest 
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Find the slope of the line that passes
Veseljchak [2.6K]

Answer:

-1/3 or -2/6

Step-by-step explanation:

First, you pick two points, I did (-5,10) and (1,8). Then, because slope is y(2)-y(1)/ x(2)-x(1), the equation would be 8-10/1-(-5) which equals -2/6 which simplifies into -1/3.

(hope this helps!)

4 0
3 years ago
If the graph of a line goes from the upper left corner of the graph to the lower right corner, what can you say about its slope?
musickatia [10]

Answer:

I believe the answer is D. Hope this helps

Step-by-step explanation:

4 0
3 years ago
BRAINLIEST FOR RIGHT ANSWER!!
julsineya [31]

Answer: {\boxed{h(x+4)=\frac{9+3x}{8+x}}}

Concept:

In a function f(x), it represents a function in terms of x or for x. Therefore, to find the values in the function, substitute values within the parenthesis to solve.

Solve:

<u>Given information</u>

h(x)=\frac{-3+3x}{4+x}

<u>Need to find</u>

h(x+4)

<u>Substitute (x + 4) to the position of x</u>

h(x+4)=\frac{-3+3(x+4)}{4+(x+4)}

<u>Distributive property on the numerator</u>

h(x+4)=\frac{-3+3x+12}{4+(x+4)}

<u>Combine like terms</u>

h(x+4)=\frac{-3+12+3x}{4+4+x}

\boxed{h(x+4)=\frac{9+3x}{8+x}}

Hope this helps!! :)

Please let me know if you have any questions

5 0
2 years ago
If anyone could do 1,2,3 or 4 that would be great! thanks and i’ll give brainliest :)
Dmitry_Shevchenko [17]

Answer:

ok i will teach all just chat me

Step-by-step explanation:

ok

7 0
3 years ago
PLEASE ANSWER ASAP! YOUR ANSWER MUST REQUIRE AN EXPLANATION IN ORDER TO RECEIVE 10 POINTS AND THE BRAINLIEST ANSWER!!! THANKS!!!
KIM [24]
Hello,

Using vectors and scalar product:

[(a+c)*\vec{i}+(b-0)*\vec{j} ].[(a-c)*\vec{i}+(b-0)*\vec{j}]=0
Thus
\dfrac{b^2}{(a+c)(a-c)}=1

By the way how can we make text larger in latex \larger{.....} don't work.

Answer A




8 0
3 years ago
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