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2 years ago

-3(2x+7)=-51 what does x=

Mathematics

1 answer:

devlian [24]2 years ago

3 0

Answer:

x=5

Step-by-step explanation:

-3(2x+7)=-51

opening bracket in the left hand side

-3.2x+(-3).7=-51

-6x-21=-51

adding 21 on both sides

-6x=-51+21

-6x=-30

dividing both sides by -6

[tex]\frac{-6x}{-6}=\frac{-30}{-6}

x=5

Hence the value of x came out to be 5

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6. Evaluate the function at each specified value of the independent variable and simplify. (If an answer is undefined, enter UND

Darya [45]

Complete Question

The complete question is shown on the first uploaded image

Answer:

$V(3) = 113.112$

$V(\frac{3}{2}) = 14.139$

$V(2r) = 33.514r^3$

$h(5) = 0$

$h(t) = -5.76$

$h(x+5) = x(x+5)$

Step-by-step explanation:

Considering the question 6

The function given is $V(r) = \frac{4}{3} \pi r^3$

For V(3) we have

$V(3) = \frac{4}{3} \pi 3^3$

$V(3) = \frac{4}{3} * 3.142 * 3^3$

$V(3) = 113.112$

For $V(\frac{3}{2})$

$V(\frac{3}{2}) = \frac{4}{3} * \pi * (\frac{3}{2})^3$

$V(\frac{3}{2}) = \frac{4}{3} * 3.142 * (\frac{3}{2})^3$

$V(\frac{3}{2}) = 14.139$

For V(2r)

$V(2r) = \frac{4}{3} \pi (2r)^3$

$V(2r) = \frac{4}{3} * 3.142*8r^3$

$V(2r) = 33.514r^3$

Considering the question 7

The function given is $h(t) = t^2 - 5t$

For h(5)

$h(5) = 5^2 - 5(5)$

$h(5) = 0$

For h(1.8)

$h(t) = 1.8^2 - 5(1.8)$

$h(t) = -5.76$

For h(x+ 5)

$h(x+5) = (x+5)^2 - 5(x+5)$

$h(x+5) = x^2 + 25+10x-5x-25$

$h(x+5) = x(x+5)$

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