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2 years ago

In the diagram below of triangle ABC, the medians meet at point G. If CF = 39, what is the length of CG?

Mathematics

1 answer:

LenKa [72]2 years ago

5 0

Applying the centroid theorem of a triangle, the length of CG is: 26.

Recall:

Medians join the vertices to the midpoint of the opposite sides of a triangle.

The center that all the three medians intersect at is called the centroid.

Based on the centroid theorem, the distant from the centroid to the vertex = 2/3 of the median length.

Triangle ABC is shown in the image attached below. G is the centroid.

CF = 39 (median)

CG = 2/3(CF) ---> Centroid Theorem.

Substitute

CG = 2/3(39)

CG = 26

Therefore, applying the centroid theorem of a triangle, the length of CG is: 26.

Learn more about centroid theorem on:

brainly.com/question/20627009

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Find the equation of the line passing through the points (3,-2) and (4, 6). y = 8x + [?]

Sauron [17]

Step-by-step explanation:

1.) Plug in one of the points.

y = 8x + b

6 = 8(4) + b

2.) Solve for b (or [?])

$6 = 32 + b \\ - 32 \: \: \: \: \: \: \: \: \: - 32$

32 cancels out on the right side.

Subtract 32 from 6, which is -26

3.) -26 = b

4.) Check with other point:

-2 = 8(3) + b

-2 = 24 + b

Cancel out 24 on the right side: 24-24 = 0

-2 - 24 = -26

-26 = b

4 0

3 years ago

The probability that a student has a Visa card (event V) is .63. The probability that a student has a MasterCard (event M) is .1

Aleksandr-060686 [28]

Answer:

a) The probability that a student has either a Visa card or a MasterCard is 0.71.

b) V and M are not independent.

Step-by-step explanation:

Given : The probability that a student has a Visa card (event V) is 0.63. The probability that a student has a MasterCard (event M) is 0.11. The probability that a student has both cards is 0.03.

To find :

a) The probability that a student has either a Visa card or a MasterCard ?

b) In this problem, are V and M independent ?

Solution :

The probability that a student has a visa card(event V) is P(V)= 0.63

The probability that a student has a MasterCard (event M) is P(M)= 0.11

The probability that a student has both cards is $P(V \cap M)=0.03$

a) Probability that a student has either a Visa card or a Master Card is given by,

$P(V \cup M) = P(V) + P(M) - P(V\cap M)$

$P(V \cup M) = 0.63+ 0.11- 0.03$

$P(V \cup M) =0.74- 0.03$

$P(V \cup M) =0.71$

The probability that a student has either a Visa card or a MasterCard is 0.71.

b) Two events, A and B, are independent if $P(A\cap B)=P(A)P(B)$

For V and M to be independent the condition is satisfied,

$P(V\cap M)=P(V)P(M)$

Substitute the values,

$0.03=0.63\times 0.11$

$0.03\neq 0.0693$

So, V and M are not independent.

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3 years ago

jan has a 12-ounce milkshake.Four ounces in the milkshake are vanilla,and the rest is chocolate.What are two equivalent fraction

bagirrra123 [75]

Answer:

In this item, we are given that out of 12 ounces of ingredients comprising the milkshake, there are 4 ounces vanilla. Expressing this into fraction will give us an answer of 4/12. This fraction can be one of the answers. Since we are asked for two fractions, we can simplify 4/12 such that we get an equivalent fraction that is equal to 2/6. Hence, the answers to this question are 4/12 and 2/6.

Step-by-step explanation:

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3 years ago

If you drive three cars from a regular deck of 52 cards for keeping each card out of the deck after you drive what are the chanc

Andreyy89

Chance to draw 7: 4 out of 52
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$\frac{2}{5525}$

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3 years ago

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asambeis [7]

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3 years ago