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Vlad [161]
3 years ago
14

How many real solutions does this system of equations have? xy = 9 y = 3x - 1

Mathematics
1 answer:
tekilochka [14]3 years ago
6 0

Answer:

two real, unequal roots

Step-by-step explanation:

y is definied as y = 3x - 1.  Substitute 3x - 1 for y in xy = 9, obtaining:

x(3x - 1) = 9.  Then:

3x^2 - x - 9 = 0.  In this quadratic, the coefficients are a = 3, b = -1 and c = -9.

Calculating the discriminant b^2 - 4ac, we get (-1)^2 - 4(3)(-9), or 1 + 108, or 109.  Because the discriminant is positive, we have two real, unequal roots.

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The Students at Sunnyside School built a rectangular pyramid of aluminum cans for a world record. The top layer had 2 rows with
Lana71 [14]
2 times 3 equals 6.and 4 times6 equals 24.and 8 times 12 equals 96 add them all together and you will get 126


HOPE THIS HELPS
If it does please press the heart thing please
7 0
4 years ago
Evaluate 5+5*5+5/5-5+5*5
rewona [7]

Answer:

51

Step-by-step explanation:

5*5=25

5/5=1

5+25+1-5+25

30+1-5+25

31-5+25

26+25

51

4 0
4 years ago
Read 2 more answers
Classify the polynomial by its degree and the number of terms. 8x²- 3y + 7
katen-ka-za [31]

Answer:

2nd degree

Step-by-step explanation:

8 0
3 years ago
The graph of part of linear function p is shown on the grid.
Rufina [12.5K]

Answer:

A

Step-by-step explanation:

The domain of a function is the span of x-values covered by the graph.

From the graph, we can see that it stretches from x=-7 to x=2.

However, note that at x=-7, the dot is closed (shaded in). In other words, x=-7 <em>is</em> in our domain.

On the other hand, at x=2, the dot is not shaded. So, x=2 is <em>not</em> included in our domain.

Therefore, our domain all are numbers between -7 and 2 including -7 (and not including 2).

As a compound inequality, this is:

-7\leq x

So, our answer is A.

Also note that we use x instead of p(x) because the domain relates to the x-variable. If we were to instead find the range, then we would use p(x).

4 0
3 years ago
Read 2 more answers
Someone help me with these two. I'll give you brainliest and 25 points!! MATHEMATICIANS OUT THERE HELP
mixer [17]
Hello LovingAngel!

To find the slope, you can use the formulas \frac{rise}{run} as well as \frac{y^2-y^1}{x^2 - x^1}. I am using the latter to calculate and ensuring my answer with the former. 

[Note: (x,y) is the format for ordered pairs]

First pair:  value 1:(1,5) and value 2:(2,8) 
\frac{y^2-y^1}{x^2 - x^1} -> \frac{8 - 5}{2 - 1} -> \frac{3}{1} or 3. 

The slope for (1,5) and (2,8) is 3(/1). 

Second pair: value 1: (3,1) value 2 (3,-1)

\frac{y^2-y^1}{x^2 - x^1} -> \frac{-1 - 1}{3 - 3} -> \frac{-2}{0}
Slope for the second pair is -2/0

Checking work with \frac{rise}{run}
1. Slope: 3/1, meaning rise (y) +3 and run (x) +1.  (1,5) -> (1+1,5 + 3) -> (2,8) ✔
2. Slope: -2/0, meaning rise (y) -2/drop (y) 2 and run 0. (3,1) -> (3 + 0, 1 + -2) -> (3,-1) <span>✔</span>

6 0
3 years ago
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