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Vlad [161]
3 years ago
14

How many real solutions does this system of equations have? xy = 9 y = 3x - 1

Mathematics
1 answer:
tekilochka [14]3 years ago
6 0

Answer:

two real, unequal roots

Step-by-step explanation:

y is definied as y = 3x - 1.  Substitute 3x - 1 for y in xy = 9, obtaining:

x(3x - 1) = 9.  Then:

3x^2 - x - 9 = 0.  In this quadratic, the coefficients are a = 3, b = -1 and c = -9.

Calculating the discriminant b^2 - 4ac, we get (-1)^2 - 4(3)(-9), or 1 + 108, or 109.  Because the discriminant is positive, we have two real, unequal roots.

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I need help with this question.
ahrayia [7]

Answer:

59

Step-by-step explanation:

We know that all the angles must add up to 180

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Scott bought a pen and received change of $4.75 in 25 coins, all dimes and quarters. How many of each kind did he receive?
dangina [55]

Answer:

He received 10 dimes and 15 quarters.

Step-by-step explanation:

Dimes = $0.10

Quarters = $0.25

Variable x = dimes

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Create a pair of linear equations:

0.10x + 0.25y = 4.75

x + y = 25

Isolate any variable, using an equation of your choice:

x + y = 25

x = 25 - y

Plug in this new value of x into the other equation:

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Use the distributive property:

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Combine like terms:

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Isolate variable y:

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x = 10

7 0
2 years ago
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