All categories

3 years ago

Find the measure of the arc or angle indicated.

Mathematics

1 answer:

xenn [34]3 years ago

7 0

For each problem, use the inscribed angle theorem.

19.

$45^\circ=\dfrac12m\widehat{QR}\implies m\widehat{QR}=90^\circ$

20.

$95^\circ=\dfrac12m\widehat{ABC}\implies m\widehat{ABC}=190^\circ$

21.

$49^\circ=\dfrac12m\widehat{LR}\implies m\widehat{LR}=98^\circ$

LN is a diameter, so arc LN has measure 180º, and so

$m\widehat{LR}+m\widehat{RN}=m\widehat{LN}=180^\circ\implies m\widehat{RN}=82^\circ$

You might be interested in

To estimate the mean height μ of male students on your campus,you will measure an SRS of students. You know from government data

nexus9112 [7]

Answer:

a) $\sigma = 0.167$

b) We need a sample of at least 282 young men.

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by

$Z = \frac{X - \mu}{\sigma}$

This Zscore is how many standard deviations the value of the measure X is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

(a) What standard deviation must x have so that 99.7% of allsamples give an x within one-half inch of μ?

To solve this problem, we use the 68-95-99.7 rule. This rule states that:

68% of the measures are within 1 standard deviation of the mean.

95% of the measures are within 2 standard deviations of the mean.

99.7% of the measures are within 3 standard deviations of the mean.

In this problem, we want 99.7% of all samples give X within one-half inch of $\mu$ . So $X - \mu = 0.5$ must have $Z = 3$ and $X - \mu = -0.5$ must have $Z = -3$ .

$Z = \frac{X - \mu}{\sigma}$

$3 = \frac{0.5}{\sigma}$

$3\sigma = 0.5$

$\sigma = \frac{0.5}{3}$

$\sigma = 0.167$

(b) How large an SRS do you need to reduce the standard deviationof x to the value you found in part (a)?

You know from government data that heights of young men are approximately Normal with standard deviation about 2.8 inches. This means that $\sigma = 2.8$

The standard deviation of a sample of n young man is given by the following formula

$s = \frac{\sigma}{\sqrt{n}}$

We want to have $s = 0.167$

$0.167 = \frac{2.8}{\sqrt{n}}$

$0.167\sqrt{n} = 2.8$

$\sqrt{n} = \frac{2.8}{0.167}$

$\sqrt{n} = 16.77$

$\sqrt{n}^{2} = 16.77^{2}$

$n = 281.23$

We need a sample of at least 282 young men.

6 0

3 years ago

During a sale a store offered a 40% discount on a particular camera that was originally price at $450 after the sale the discoun

Artemon [7]

£378

$450×0.6=$270.

$270×1.4=$378

3 0

4 years ago

8. Solve using any method.<br> 3y – 3 = 3x<br> -3x + 3y = -57

Ksivusya [100]

Answer:

No Solutions.

Step-by-step explanation:

I will solve your system by substitution.

3y−3=3x; −3x+3y=−57

Step: Solve 3y−3=3x for y:

3y−3+3=3x+3 (Add 3 to both sides)

3y=3x+3

(3y/3=3x+3)/3

(Divide both sides by 3)

y=x+1

Step: Substitute x+1 for y in −3x+3y=−57:

−3x+3y=−57

−3x+3(x+1)=−57

3=−57 (Simplify both sides of the equation)

3+(−3)=−57+(−3) (Add -3 to both sides)

0=−60

5 0

3 years ago

Anybody know how to do Special Right Triangles for geometry if so could you explain how to do it.

Lina20 [59]

Step 1: This is a right triangle with two equal sides so it must be a 45°-45°-90° triangle. Step 2: You are given that the both the sides are 3. If the first and second value of the ratio x:x:x√2 is 3 then the length of the third side is 3√2. Answer: The length of the hypotenuse is 3√2 inches.

3 0

3 years ago

The model of a trinomial is shown. An algebra tile configuration. 0 tiles are in the Factor 1 spot and 0 tiles are in the Factor

Snezhnost [94]

Answer:

C. x – 7

E. x + 2

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

Find the measure of the arc or angle indicated.​

Find the measure of the arc or angle indicated.