The answer would be b.)AaBbCc<span>They because will receive one recessive </span>allele<span> from their father and one </span>dominant<span> allele from their mother at each </span>gene<span> locus.</span>
Answer:
C. It is a male with atleast one dominant allele
Explanation:
In the given pedigree, the two normal parents of the generation I have one daughter with the attached earlobe. Since the trait is recessive, the daughter should be homozygous recessive to express the trait. The genotype of the daughter (shaded circle in generation II) is "aa". To have a daughter with "aa" genotype, both the parents should have one copy of "a" allele. So, the genotype of both parents is "Aa".
In generation II, individual A is non-shaded square. Squares represent males in a pedigree. Since its not shaded, it does not have attached earlobe. Both the parents are heterozygous dominant for attached earlobes (Aa x Aa = 1/4 AA : 1/2 Aa : 1/4 aa). The genotype of this individual may be AA or Aa.
According to the observation, I would conclude that the fungus has asexual form of reproduction. This is because asexual spores germinate and produce new hyphae anytime and anywhere as long as the conditions are favorable. Sexual pores on the other hand need a time of dormancy after the are formed before they produce more hyphae.
According to sources, the most probable answer to this query is allostasis. This the body's way of being able to cope with stressful situations and respond accordingly.
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