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BARSIC [14]
3 years ago
14

During pregnancy, a cell undergoes what appears to be a normal mitotic nuclear division. However, two daughter cells with 2n-1 a

nd 2n+1 complement of chromosomes are produced, causing a population of cells to be abnormal. Which of the following events is most likely responsible for this disorder?
a. The cleavage furrow did not completely separate the two daughter cells.
b. Homologous chromosomes were sorted incorrectly during prophase.
c. Two sister chromatids did not separate into the proper daughter cells during anaphase.
d. The protein structure of nonkinetochore microtubules was defective, and incorrectly shortened during anaphase.
Biology
1 answer:
dem82 [27]3 years ago
8 0

Answer:

c. Two sister chromatids did not separate into the proper daughter cells during anaphase.

Explanation:

The observed cell is undergoing mitosis which does not include separation of homologous chromosomes. During anaphase of mitosis, two sister chromatids of each chromosome separate from each other. They move to opposite poles. This results in equal distribution of two complete sets of chromosomes to each daughter cell.

However, the failure of two sister chromatids of a chromosome during anaphase would lead to the formation of two abnormal daughter cells. One of the daughter cells would have one extra chromosome (2n+1) while the other would lack one chromosome from the diploid set (2n-1).

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How many new volumes would each new cell contain whenever a cell splits?
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Another moment of increasing volume of the cell and now also related to cell division would be during the two stages in the cell cycle (i.e., G1 and G2 phases). This is the growth phase of the cell preparing to divide. However when mitosis or division happens, the cells will normally end with the same volume as when it started.

This are safe generalizations referring to the human cells. It would help if a more specific kind of cell was given.
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3 years ago
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Answer:

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8 0
2 years ago
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