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3 years ago

Z=a/b+c/d solve for A

Mathematics

1 answer:

PilotLPTM [1.2K]3 years ago

6 0

Answer: $a=\frac{b(zd-c)}{d}$

Step-by-step explanation:

Having the following equation given in the exercise:

$z=\frac{a}{b}+\frac{c}{d}$

You can solve for "a" following this procedure:

1. You can apply the Subtraction property of equality and subtract $\frac{c}{d}$ from both sides of the equation:

$z-(\frac{c}{d})=\frac{a}{b}+\frac{c}{d}-(\frac{c}{d})\\\\z-\frac{c}{d}=\frac{a}{b}$

2. Now you must subtract the terms on the left side of the equation. Notice that the Least Common Denominator is "d". Then:

$\frac{zd-c}{d}=\frac{a}{b}$

3. Finally, you can apply the Multiplication property of equality and multiply both sides of the equation by "b". So, you get:

$(b)(\frac{zd-c}{d})=(\frac{a}{b})(b)\\\\a=\frac{b(zd-c)}{d}$

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3 years ago

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Answer:

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Step-by-step explanation:

Given

$(x_1,y_1) = (2,\frac{2}{3})$

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Required

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