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4 years ago

Write an inequality for each sentence.

1 answer:

5 0

#2: Her earnings were no more than $64. Let e represent her earnings. E is less than or equal to 64 (since it says no more than $64).

e ≤ 64.

#4: A checking account was no more than $500. Let a represent the amount in the checking account. A is less than or equal to 500.

a ≤ 500.

#5: Max. ceiling height of 8 ft is required. Let f represent length in feet. Length in feet has to be less than or equal to 8.

f ≤ 8.

#6: Min. number of 12 participants required. Let n represent the number of participants. There has to be at LEAST 12 participants. So, the number of participants has to be greater than or equal to 12.

n ≥ 12.

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PLEASE SOMEONE HELP! Thanksss

marusya05 [52]

Answer:

Ф=144

Ф =s/r ( Ф is the central angle,s is the arc length, r is the radius)

find r:

radius =circumference/2π=1/2π=0.16

Ф=(2/5) /(1/2π)=4π/5=144 degree (π=180)

Ф in degrees: 144 degrees

3 0

3 years ago

Suppose M is the midpoint of Segment AB, P is the midpoint of Segment AM, and Q is the midpoint of segment PM.

DerKrebs [107]

The coordinates of M, P and Q in terms of a and b are $M = \frac{1}{2}\cdot a + \frac{1}{2}\cdot b$ , $P = \frac{3}{4}\cdot a + \frac{1}{4}\cdot b$ and $Q = \frac{1}{8}\cdot a - \frac{1}{8}\cdot b$ , respectively.

In this question we are going to use definitions of vectors and product of a vector by a scalar. Based on the information given on statement, we have the following vectorial formulas:

Location of M

$\overrightarrow{AM} = \frac{1}{2}\cdot \overrightarrow{AB}$

$\vec M - \vec A = \frac{1}{2}\cdot \vec B - \frac{1}{2}\cdot \vec A$

$\vec M = \frac{1}{2}\cdot \vec A +\frac{1}{2}\cdot \vec B$

$M = \frac{1}{2}\cdot a + \frac{1}{2}\cdot b$

Location of P

$\overrightarrow{AP} = \frac{1}{2}\cdot \overrightarrow{AM}$

$\vec P - \vec A = \frac{1}{2}\cdot \vec M - \frac{1}{2}\cdot \vec A$

$\vec P = \frac{1}{2}\cdot \vec A +\frac{1}{2}\cdot \vec M$

$\vec P = \frac{3}{4}\cdot \vec A + \frac{1}{4}\cdot \vec B$

$P = \frac{3}{4}\cdot a + \frac{1}{4}\cdot b$

Location of Q

$\overrightarrow{QM} = \frac{1}{2}\cdot \overrightarrow{PM}$

$\vec M - \vec Q = \frac{1}{2}\cdot \vec M - \frac{1}{2}\cdot \vec P$

$\vec Q = \frac{1}{2}\cdot \vec P - \frac{1}{2}\cdot \vec M$

$\vec Q = \frac{1}{2}\cdot \left(\frac{3}{4}\cdot \vec A + \frac{1}{4}\cdot \vec B\right) -\frac{1}{2}\cdot \left(\frac{1}{2}\cdot \vec A + \frac{1}{2}\cdot \vec B\right)$

$\vec Q = \frac{1}{8}\cdot \vec A -\frac{1}{8}\cdot \vec B$

$Q = \frac{1}{8}\cdot a - \frac{1}{8}\cdot b$

We kindly invite to check this question on midpoints: brainly.com/question/4747771

4 0

2 years ago

I need help, please im stuck on this problem

Mazyrski [523]

Answer:

0.035 gram....

Step-by-step explanation:

.........

7 0

2 years ago

Read 2 more answers

9) The present ages of Juna and Jubin are in the ratio 5:8. After 4 years the sum

vodka [1.7K]

Answer:

Present age of Juna = 10 years

Present age of Jubin = 16 years

Step-by-step explanation:

Ratio of present ages = 5: 8

Let the present ages of:

Juna be 5x years and Jubin be 8x years

(where x is the common multiplier of the given ratios)

Four years after:

Juna's age = (5x + 4) years

Jubin's age = (8x + 4) years

According to the question:

(5x + 4) + (8x + 4) = 34

13x + 8 = 34

13x = 34 - 8

13x = 26

x = 26/13

x = 2

5x = 5*2 = 10 years

8x = 8*2 = 16 years

Hence,

Present age of Juna = 10 years

Present age of Jubin = 16 years

4 0

3 years ago

What is the solution to 3/4 (x+8) > 1/2 (2x+10)

densk [106]

Answer:

3/4x+2>x+5
3/4x-x>-8+5
-1/4x>-3
x>12

3 0

2 years ago