The following set of data represents letter grades on term papers in a rhetoric class: A,A,A,B,B,B,B,C,C,C,C,C,C,C,C,C,D,D,D,F.
Viktor [21]
Answer:
c. Mode
Step-by-step explanation:
Mean is the average obtained by adding all values and then dividing by the size of the values. Here, adding A and B etc is not clear.
Median is the middle value of a set of numeric values. To find a median, values should be sort-able from smallest to the largest. If there is no unique middle value, then the average of the middle values has to be taken. Here, average of the two different grades is not clear.
Mode is the value that occurs most often. Clearly C occurs most often.
Mid-range value is the mean of the difference between largest value and the smallest value. Here, difference between A and F is not clear.
Mean,median,Mid-range are applied to numeric values where mode is also suitable for categorical values.
Therefore, the most appropriate measure of central tendency for the data described is mode
What you have here is the fibonacci sequence.
Each number in the sequence adds itself to the number before it.
1+1 = 2
1+2 = 3
3+2 = 5
5+3 = 8
8+5 = 13
the sequence is 0,1,1,2,3,5,8,13
Answer:
8/18=4/9
Step-by-step explanation:
since it there is 1/6 for red marbles and 5/18 for blue marbles it works because it is 8*9=72 for the denominator and 4*3=12 so it is 12/72=1/6 and for blue it is 5/18 because it is 5*4=20 and 20/72=10/36=5/18 so it is 1/6+5/18=8/18=4/9
Times the bottom equation by -4 to cancel out the x’s.
Add the equations.
Solve for y.
Plug in y to find x.
