How do you get the number 43 with the numbers 2,3,6,8 with using all numbers and only using them once.
1 answer:
You might be interested in
First, you should solve for 
, which equals 
. Now, solve the integral of =, to get that
. You can check this by taking the integral of what you got. Now by the Fundamental Theorem![\int\limits^2_0 {4x} \, dx=[2x^2] ^{2}_{0}=2(2)^{2}-2(0)^2=8](https://tex.z-dn.net/?f=%20%5Cint%5Climits%5E2_0%20%7B4x%7D%20%5C%2C%20dx%3D%5B2x%5E2%5D%20%5E%7B2%7D_%7B0%7D%3D2%282%29%5E%7B2%7D-2%280%29%5E2%3D8)
.
This should be the answer to your question, if I understood what you were asking correctly.
This should be the answer to your question, if I understood what you were asking correctly.