Answer:
I = 1.4 [amp]
Explanation:
To solve this problem we must use ohm's law, which tells us that the voltage is equal to the product of the current by the resistance.
Therefore:
V = I*R
where:
V = voltage = 14[V]
I = current [amp]
R = resistance = 10 [ohm]
I = 14/10
I = 1.4 [amp]
The current through the heater is 8 A if potential difference is increased to 120 V.
Explanation:
- According to Ohm's Law, the potential difference (Voltage) is directly proportional to the current flowing through a conductor.
That is, V ∝ I
⇒ V = IR where R is the constant of proportionality called resistance.
- In this case, given voltage = 60 V and current = 4 A. To find the current, first find the constant of proportionality, resistance of the heater.
R = V/I = 60/4 = 15 ohm
- If the potential difference is increased to 120 V, find the current flowing through it.
I = V/R = 120/15 = 8 A
The jet fighter's acceleration at the highest point is 17.56 ft/s²
The jet fighter's acceleration at the lowest point is 35.12 ft/s²
The given parameters;
radius of the circular path, r = 1200 ft
constant velocity, v = 140 mi/h = 205.3 ft/s
The formula for centripetal acceleration in a circular path is given as;

The jet fighter's acceleration at the highest point is calculated as;
h = 2r = 2 x 1200 ft = 2,400 ft

The jet fighter's acceleration at the lowest point is calculated as;
h = r = 1,200 ft

Learn more here:brainly.com/question/11700262
#4). The concepts are: A). acceleration is always in the direction of the force, and B). friction always acts in the direction opposite to motion. (that's B)
#5). The concepts are: A). the NET force is the sum of all the individual forces acting (on this car, it's 1600N forward). and B). Force = (mass) x (acceleration). So Acceleration = (force) / (mass). For this car, that's (1600N forward) / (800 kg) .
#6). The concept is: As long as you don't exceed the "proportionality limit" of a spring, its extension is proportional to the load on it. That means that the change in extension is always proportional to the change in the load. So now, look at the table: As long as the load is 10N or less, the spring stretched 3cm longer for every 2N more of load. But if the load is somewhere between 10N and 12N, that relationship disappears. Something changes between 10N and 12N of load. The spring's "elastic limit" is somewhere in that slot.
260 joules is hopefully right.