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lord [1]
3 years ago
6

I have to submit my homework soon and I am not familiar with these concepts. can anybody do then for me?

Physics
1 answer:
AlladinOne [14]3 years ago
6 0

#4).  The concepts are:  A). acceleration is always in the direction of the force, and B). friction always acts in the direction opposite to motion.  (that's B)

#5).  The concepts are:  A). the NET force is the sum of all the individual forces acting (on this car, it's 1600N forward).  and B). Force = (mass) x (acceleration).  So Acceleration = (force) / (mass).  For this car, that's (1600N forward) / (800 kg) .

#6).  The concept is:  As long as you don't exceed the "proportionality limit" of a spring, its extension is proportional to the load on it.  That means that the change in extension is always proportional to the change in the load.  So now, look at the table:  As long as the load is 10N or less, the spring stretched 3cm longer for every 2N more of load.  But if the load is somewhere between 10N and 12N, that relationship disappears.  Something changes between 10N and 12N of load.  The spring's "elastic limit" is somewhere in that slot.


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In a discussion person A is talking 1.2 dB louder than person B, and person C is talking 3.2 dB louder than person A. What is th
liberstina [14]

Answer: 3.84dB

Explanation:

Since person A is talking 1.2dB louder than B, we will have

A = 1.2B... (1)

Similarly, person C is talking 3.2 dB louder than person A, we have

C = 3.2A... (2)

From equation 1, B = A/1.2... (3)

To get the ratio of the sound intensity of person C to the sound intensity of person B, we will divide equation 2 by 3 to give

C/B = 3.2A/{A/1.2}

C/B = 3.2A×1.2/A

C/B = 3.2×1.2

C/B = 3.84dB

3 0
3 years ago
Match the term with the appropriate image
Tamiku [17]

First figure shows the object position

Second shows the image position

Third shows the focal length.

8 0
3 years ago
Why the change of the pressure and temperature affect the velocity of the sound ​
Marysya12 [62]

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5 0
3 years ago
In a high school swim competition, a student takes 1.6 s to complete 1.5 somersaults. Determine the average angular speed of the
Rufina [12.5K]

Answer:

The  angular speed is w = 5.89 \ rad/s

Explanation:

From the question we are told that

    The time taken is  t = 1.6 s

    The number of somersaults  is n  =  1.5

The total angular displacement during the somersault is mathematically represented as

         \theta  =  n *  2 *  \pi

substituting values

        \theta  =  1.5 *  2 *  3.142

       \theta  = 9.426 \ rad

 The angular speed is mathematically represented as

         w =  \frac{\theta }{t}

substituting values

         w =  \frac{9.426}{1.6}

          w = 5.89 \ rad/s

     

3 0
3 years ago
Density of iron in CGS unit is 7.8 g/cm3. Its density is SI is
kumpel [21]

Answer:

7800kg/m³

Explanation:

Density of iron in CGS unit is 7.8 g/cm3. Its density is SI is

Given the density of iron = 7.8 g/cm3.

The SI units must be in kg/m³

7.8g = 7.8/1000 kg

7.8g = 0.0078kg

1cm³ = 0.000001m³

7.8g/cm³

= 0.0078/0.000001 kg/m³

= 7800kg/m³

Hence the density in SI unit is 7800kg/m³

4 0
3 years ago
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