I have to submit my homework soon and I am not familiar with these concepts. can anybody do then for me?
1 answer:
#4). The concepts are: A). acceleration is always in the direction of the force, and B). friction always acts in the direction opposite to motion. (that's B)
#5). The concepts are: A). the NET force is the sum of all the individual forces acting (on this car, it's 1600N forward). and B). Force = (mass) x (acceleration). So Acceleration = (force) / (mass). For this car, that's (1600N forward) / (800 kg) .
#6). The concept is: As long as you don't exceed the "proportionality limit" of a spring, its extension is proportional to the load on it. That means that the change in extension is always proportional to the change in the load. So now, look at the table: As long as the load is 10N or less, the spring stretched 3cm longer for every 2N more of load. But if the load is somewhere between 10N and 12N, that relationship disappears. Something changes between 10N and 12N of load. The spring's "elastic limit" is somewhere in that slot.
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Answer:
A) If the paintball stops completely the magnitude of the change in the paintball’s momentum is
B) If the paintball bounces off its target and afterward moves in the opposite direction with the same speed, the change in the paintball’s momentum is
C) A paintball bouncing off your skin in the opposite direction with the same speed hurts more than a paintball exploding upon your skin because of the strength exerted is twice than if it explodes.
Explanation:
Hi
A) We use the formula of momentum , so we have
B) We use the same formula above, then due we have a change of direction at the same speed, therefore the change in the momentum is the double so
.
C) The average strength of the force an object exerts during impact is determined by the amount the object’s momentum changes. therefore
, as we don't have any data about the impact time but we know momentum is twice, time does no matter and strength is twice too.
a) 10 m/s
b) 25 m
Explanation:
a)
The body is moving with a constant acceleration, therefore we can solve the problem by using the following suvat equation:
where
u is the initial velocity
v is the final velocity
a is the acceleration
t is the time
For the body in this problem:
u = 0 (the body starts from rest)
is the acceleration
t = 5 s is the time
So, the final velocity is
b)
In this second part, we want to calculate the distance travelled by the body.
We can do it by using another suvat equation:
where
u is the initial velocity
v is the final velocity
a is the acceleration
s is the distance travelled
Here we have
u = 0 (the body starts from rest)
is the acceleration
v = 10 m/s is the final velocity
Solving for s,