Answer:
Explanation:
Given that,
Small wheel applied force
F₁ = 50N
Small wheel radius
r₁ = 18cm
Bigger wheel radius.
r₂ = 29cm
Bigger wheel applied force
F₂ =?
Since the combination of those forces did not cause the wheel to rotate,
Then, Στ = 0
F₁•r₁ —F₂•r₂ =
50×18 — 29F₂ = 0
900 = 29F₂
F₂ = 900 / 29
F₂ = 31.03 N
The pulling force applied at the larger wheel is 31.03N
To solve this problem it is necessary to address the concepts related to Torque as a function of the force and distance where it is applied and the moment of inertia from which the torque, moment of inertia and angular acceleration are related.
By definition the torque is defined as

Where,

F = Force
r = Radius
For our values we have:



Consequently the calculation of the moment of inertia would then be given by the relationship


Replacing with our values


The moment of inertia of the boxer's forearm 
Explanation:
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Answer:
South ....................
The equation for the energy (E) of the electron may be obtained by the equation,
E = hc / λ
where h is Planck's constant, c and λ are speed of light and wavelength, respectively. Substituting the values,
(-2.179x10^-18 - -8.720x10^-20) = (6.626x10^-34)(2.998x10^8)/ λ
From the equation, the value of λ is approximately equal to 9.496x10^-8 m.