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lord [1]
2 years ago
6

I have to submit my homework soon and I am not familiar with these concepts. can anybody do then for me?

Physics
1 answer:
AlladinOne [14]2 years ago
6 0

#4).  The concepts are:  A). acceleration is always in the direction of the force, and B). friction always acts in the direction opposite to motion.  (that's B)

#5).  The concepts are:  A). the NET force is the sum of all the individual forces acting (on this car, it's 1600N forward).  and B). Force = (mass) x (acceleration).  So Acceleration = (force) / (mass).  For this car, that's (1600N forward) / (800 kg) .

#6).  The concept is:  As long as you don't exceed the "proportionality limit" of a spring, its extension is proportional to the load on it.  That means that the change in extension is always proportional to the change in the load.  So now, look at the table:  As long as the load is 10N or less, the spring stretched 3cm longer for every 2N more of load.  But if the load is somewhere between 10N and 12N, that relationship disappears.  Something changes between 10N and 12N of load.  The spring's "elastic limit" is somewhere in that slot.


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Option (c)

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Anna and Jon sit on a seesaw. Anna has a mass of 60 kg and sits 2 m from the center. Jon has a mass of 70 kg. How far from the c
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Answer:

dJ = 1.7 m

Explanation:

The Equation of the Balancing the moments in the center of the seesaw  is like this:

∑Mo = 0

Mo = F*d

Where:

∑Mo : Algebraic sum of moments in the center(o) of the balance

Mo : moment in the o point ( N*m)

F  : Force ( N)

d  : distancia of the force to the the o point  ( N*m)

Data

mA = 60 kg : mass of the Anna

mJ = 70 kg :  mass of theJon

dA = 2 m : Distance from Anna to the center of the seesaw

g: acceleration due to gravity

Calculation of the distance from Jon to the center of the seesaw  (dJ)

∑Mo = 0   WA : Ana's weight   , WJ : Jon's weight

W = m*g

(WA)(dA) - (WJ) (dJ) = 0

(mA*g)(dA) - (mJ*g)(dJ) = 0

We divide by g the equation:

(mA)(dA) - (mJ)(dJ)= 0

(mA)(dA) = (mJ)(dJ)

d_{J} = \frac{m_{A} *d_{A}}{m_{J}}

d_{J} = \frac{60 kg *2 m}{70 kg}

dJ = 1.7 m

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