Answer:
Question: Where is the following?
Answer:
I believe it is the Second Option as all the others are correct.
I don’t know. It’s an independence thing from society I guess
Answer:
Option A is the correct answer for the above question.
Explanation:
An information system is responsible to produce information after processing the data which is the input for its. The organization takes help from the computer system because the computer system is used to process the data and produce the information. The operation team of this organization is used to manage the machine of the system which is the computer system. It is because the computer system is the machine of the information system.
The above-question statement asked about the team or group which is responsible to maintain the machine of the system and the team is known as the operation team which is stated from option A. Hence option A is the correct answer for the above question. while the other is not because--
- Option B states about the technology which is not a team in the organization.
- Option C states about the development team which is used to make the software or information in the organization.
- Option D states about the maintenance team which is also not any team in the organization of information system.
Answer:
<em>import java.util.Scanner;</em>
<em>public class ANot {</em>
<em> public static void main(String[] args) {</em>
<em> Scanner in = new Scanner(System.in);</em>
<em> System.out.println("Please enter a string of words");</em>
<em> String n = in.nextLine();</em>
<em> int count = 0;</em>
<em> for (int i=0; i<n.length(); i++){</em>
<em> if((n.charAt(i) != '.') &&(n.charAt(i) != ',') && (n.charAt(i) != ' ')){</em>
<em> count++;</em>
<em> }</em>
<em> }</em>
<em> System.out.println(count);</em>
<em> }</em>
<em>}</em>
Explanation:
- Prompt User to input the string and assign to a variable
- SET count =0.
- Using a for loop iterate over the string
- if((n.charAt(i) != '.') &&(n.charAt(i) != ',') && (n.charAt(i) != ' ')) then count =count +1.
- PRINT count.
