This sounds pretty easy, in fact. The orbital motion can be assumed to be circular and with constant speed. Then, the period is the time to do one revolution. The distance is the length of a revolution. That is 2*pi*R, where R is the distance between the Moon and the Earth (the respective centers to be precise). In summary, it's like a simple motion with constant speed:
v = 2*pi*R/T,
you have R in m and T is days, which multiplied by 86,400 s/day gives T in seconds.
Then v = 2*pi*3.84*10^8/(27.3*86,400) = 1,022.9 m/s ~ 1 km/s (about 3 times the speed of sound :)
For the Earth around the Sun, it would be v = 2*pi*149.5*10^9/(365*86,400)~ 29.8 km/s!
I know it's not in the problem, but it's interesting to know how fast the Earth moves around the Sun! And yet we do not feel it (that's one of the reasons some ancient people thought crazy the Earth not being at the center, there would be such strong winds!)
A) travel outside the necleus
Answer:
The answer is temperature
Get the amount of money in a day, (8)(7)=$56 per day
5 days per week, 56(5)=280
To conclude, she gets $280 in a week.
Answer:
t = 25.5 min
Explanation:
To know how many minutes does Richard save, you first calculate the time that Richard takes with both velocities v1 = 65mph and v2 = 80mph.
Next, you calculate the difference between both times t1 and t2:
This is the time that Richard saves when he drives with a speed of 80mph. Finally, you convert the result to minutes:
hence, Richard saves 25.5 min (25 min and 30 s) when he drives with a speed of 80mph
