The first thing you should know for this case is the definition of distance.
d = v * t
Where,
v = speed
t = time
We have then:
d = v * t
d = 9 * 12 = 108 m
The kinetic energy is:
K = ½mv²
Where,
m: mass
v: speed
K = ½ * 1500 * (18) ² = 2.43 * 10 ^ 5 J
The work due to friction is
w = F * d
Where,
F = Force
d = distance:
w = 400 * 108 = 4.32 * 10 ^ 4
The power will be:
P = (K + work) / t
Where,
t: time
P = 2.86 * 10 ^ 5/12 = 23.9 kW
answer:
the average power developed by the engine is 23.9 kW
Magna Carta. I’m pretty sure it’s the correct answer.
Answer:
I think it’s the third one
Given: A cubic tank holds 1,000.0 kg of water.
Mass of water in tank (m) = 1000.0 kg
Density of water (d) = 1000.0 kg /m³
Concept: Volume(V) = Mass / Density
Since the tank holds these water in it so the volume of water will be equal to the volume of the tank.
Hence, the volume of the tank = Mass of water / Density of water
or, = 1000.0 kg / 1000.0 kg m⁻³
or, = 1.0 m³
Since tank is cubical in shape. Let its side be 'x'
The volume of tank (x³) = 1.0 m³
or. side of tank (x) = 1.0 m
Hence, the dimensions of the tank will be 1.0 m.
