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Ahat [919]
3 years ago
10

Find the value of f(g(-2)) f(x) =-2x+14 g(x)=3x^2+6x-2

Mathematics
1 answer:
Rzqust [24]3 years ago
3 0

Answer:

-2

Step-by-step explanation:

f[g(x)

=f(3x^2+6x-2)

=2 (3x^2+6x-2)+14

=6x^2+12x-4+14

=6x^2+12x+10

f[g(-2)]=6 (-2)^2+12×(-2)+10

=12- 24+10

=-2

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3/8=r+2/3 PLease help im really lazy
stira [4]

Answer:

- 7/24

Step-by-step explanation:

Step 1:

3/8 = r + 2/3

Step 2:

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Marta runs a mandarin-orange fruit stand. She is talking to an employee, Maribel, on the phone and trying to tell her the equati
Ivanshal [37]

Answer:

Fifty more than half the number of the oranges is one-hundred-and-twenty.

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Step-by-step explanation:

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Assume the number of oranges=m

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All statement that applies includes:

1. Fifty more than half the number of the oranges is one-hundred-and-twenty.

50+1/2m=120

2. The sum of fifty and half the number of oranges is the same as one-hundred-twenty.

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8 0
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My kid already tried 3x7x7x7x7 = 3 x 7 to the power of 4 but it says it’s wrong, help please!
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6 0
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The exponential decay graph shows the expected depreciation for a new boat, sell g for $3500, over 10 years.
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Okay, the exponential function is
g = a^{x}
The start price of it in t=0 is 3,500, as we can see on the graph. Then, the function becomes
g = 3500^{x}
Let's see at t=2, where the price is g=2000:
2000 =  3500^{x}
Take natural logarithm:
ln 2000 = ln  3500^{x}
x*ln 3500 = ln 2000
x = \frac{ln 2000}{ln 3500} = 0.93
So, the difference between t=0 and t=2 is
x_{t=0}  -  x_{t=2}  = 1 - 0.93 = 0.07
And then we get the change of x in one year equal to 0.035.
So, the final equation is
g =  3500^{1-0.035t}
You can insert any t and see that it is correct, for example t=7
8 0
3 years ago
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