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alexandr402 [8]
3 years ago
15

Charlie used a regression calculator to generate the

Mathematics
2 answers:
Firdavs [7]3 years ago
8 0

Answer:

Answer below, let me know if it didn't make sense.  

Step-by-step explanation:

I attached a picture of the scatterplot with a line connecting the points.  There is a definite upside down u type shape, and it doesn't look close to a line at all, so linear is not a good choice.  

an upside down u shape (or right side up u shape for that matter) is exactly what a quadratic is, or any polynomial if you do it right, but quadratic is the simplest, so let's go with that.

slamgirl [31]3 years ago
3 0

Answer:

Sample Response: The r-value for the linear function related to the ordered pairs is very close to zero, so it is not a good representation of the data. A quadratic model would better represent the data because there is a turning point within the data set. The data increases then decreases, which is what the graph of a quadratic does.

Step-by-step explanation:

:)

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the cost of annual tution design at a university increased from 10,500 to $11,300. what is the percent increase in tution to the
tangare [24]
For this case we can make the following rule of three:
 $ 10500 -------> 100%
 $ 11300 -------> x
 Clearing the value of x we have:
 x = (11300/10500) * (100)
 x = 107.6190476
 The percentage of growth is:
 107.6190476 - 100 = 7.6190476%
 Round to the nearest tenth:
 7.6%
 Answer:
 
the percent increase in tution is:
 
7.6%
8 0
4 years ago
A random sample of 20 recent weddings in a country yielded a mean wedding cost of $ 26,388.67. Assume that recent wedding costs
Makovka662 [10]

Answer:

a) 95% confidence interval for the mean​cost, μ​, of all recent weddings in this country = (22,550.95, 30,226.40)

.The​ 95% confidence interval is from $22,550.95 to $30,226.40.

b) For the interpretation of the result, option D is correct.

We can be​ 95% confident that the mean​ cost, μ​, of all recent weddings in this country is somewhere within the confidence interval.

c) Option B is correct.

The population mean may or may not lie in this​ interval, but we can be​ 95% confident that it does.

Step-by-step explanation:

Sample size = 20

Sample Mean = $26,388.67

Sample Standard deviation = $8200

Confidence Interval for the population mean is basically an interval of range of values where the true population mean can be found with a certain level of confidence.

Mathematically,

Confidence Interval = (Sample mean) ± (Margin of error)

Sample Mean = 26,388.67

Margin of Error is the width of the confidence interval about the mean.

It is given mathematically as,

Margin of Error = (Critical value) × (standard Error of the mean)

Critical value will be obtained using the t-distribution. This is because there is no information provided for the population mean and standard deviation.

To find the critical value from the t-tables, we first find the degree of freedom and the significance level.

Degree of freedom = df = n - 1 = 20 - 1 = 19.

Significance level for 95% confidence interval

(100% - 95%)/2 = 2.5% = 0.025

t (0.025, 19) = 2.086 (from the t-tables)

Standard error of the mean = σₓ = (σ/√n)

σ = standard deviation of the sample = 8200

n = sample size = 20

σₓ = (8200/√20) = 1833.6

99% Confidence Interval = (Sample mean) ± [(Critical value) × (standard Error of the mean)]

CI = 26,388.67 ± (2.093 × 1833.6)

CI = 26,388.67 ± 3,837.7248

99% CI = (22,550.9452, 30,226.3948)

99% Confidence interval = (22,550.95, 30,226.40)

a) 95% confidence interval for the mean​cost, μ​, of all recent weddings in this country = (22,550.95, 30,226.40)

.The​ 95% confidence interval is from $22,550.95 to $30,226.40.

b) The interpretation of the confidence interval obtained, just as explained above is that we can be​ 95% confident that the mean​ cost, μ​,of all recent weddings in this country is somewhere within the confidence interval

c) A further explanation would be that the population mean may or may not lie in this​ interval, but we can be​ 95% confident that it does.

Hope this Helps!!!

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3 years ago
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The answer is 0.25827f(0)2(pi)
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Find the midpoint of the line segment with the given endpoints (-1,-6) (-6,5)
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The correct answer is (-7/2,-1/2) or (-3.5,-0.5)  To find the midpoint of a segment, add both "x" coordinates, divide by 2.  Then add both "y" coordinates, and divide by 2

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