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3 years ago

Charlie used a regression calculator to generate the

Mathematics

2 answers:

Firdavs [7]3 years ago

8 0

Answer:

Answer below, let me know if it didn't make sense.

Step-by-step explanation:

I attached a picture of the scatterplot with a line connecting the points. There is a definite upside down u type shape, and it doesn't look close to a line at all, so linear is not a good choice.

an upside down u shape (or right side up u shape for that matter) is exactly what a quadratic is, or any polynomial if you do it right, but quadratic is the simplest, so let's go with that.

slamgirl [31]3 years ago

3 0

Answer:

Sample Response: The r-value for the linear function related to the ordered pairs is very close to zero, so it is not a good representation of the data. A quadratic model would better represent the data because there is a turning point within the data set. The data increases then decreases, which is what the graph of a quadratic does.

Step-by-step explanation:

You might be interested in

I’m actually confused.

-BARSIC- [3]

M^2 + n^2

Step 1:
Substitute in the numbers
-5^2 + 3^2

Step 2:
Square both numbers
25 + 9

Step 3:
Add them together

Answer is 34

8 0

3 years ago

3. The student council is selling roses to collect funds for a charity. The graph be

dexar [7]

Answer:

$Unit = 3$

Step-by-step explanation:

Given

See attachment for graph

Required

The unit cost

Pick any point on the dots of the graph; we have:

$(x,y) = (2,6)$

The unit cost is then calculated as:

$Unit = \frac{6}{2}$

$Unit = 3$

5 0

3 years ago

In ΔOPQ, the measure of ∠Q=90°, OQ = 80, QP = 39, and PO = 89. What ratio represents the cosecant of ∠P?

Serjik [45]

Answer:

cos(O) = 39 / 89

Step-by-step explanation:

Given:

ΔOPQ, where

∠Q=90°

PO = 89

OQ = 39

QP = 80

cosine of ∠O?

cos(O) = Adjacent / Hypotenuse

cos(O) = 39 / 89

3 0

3 years ago

Read 2 more answers

Solve each equation by completing the square 2q^2+8q=3

3241004551 [841]

Answer:

Divide by 2

q^2+4q=3/2

q^2+4q(4/2)^2=3/2+(4/2)^2

(q+4/2)^2=3/2+16/4

taking the square root of both side

√(q+4/2)^2=√(3/2+16/4)

Note that the square will cancel the square root then you will take LCM on the right hand side

q+4/2=√6+16/4

q+4/2=√22/4

q= -4/2+-√22/4

q=(-4+_√22/4)

5 0

3 years ago

A sanitation department is interested in estimating the mean amount of garbage per bin for all bins in the city. In a random sam

soldi70 [24.7K]

Answer:

a) $52.8-2.02\frac{3.9}{\sqrt{40}}=51.554$

b) $52.8+2.02\frac{3.9}{\sqrt{40}}=54.046$

c) $52.8-2.71\frac{3.9}{\sqrt{40}}=51.129$

d) $52.8+2.71\frac{3.9}{\sqrt{40}}=54.471$

e) Yes, depends of the confidence level.

At 95 % of confidence the value 54.1985 pounds is not included on the interval. At 5% of significance the statement is FALSE.

At 99 % of confidence the value 54.1985 pounds is included on the interval. So at 1% of significance the statement is TRUE.

Step-by-step explanation:

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$\bar X =52.8$ represent the sample mean for the sample

$\mu$ population mean (variable of interest)

s=3.9 represent the sample standard deviation

n=40 represent the sample size

a) What is the lower limit of the 95% interval? Give your answer to three decimal places

The confidence interval for the mean is given by the following formula:

$\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}$ (1)

In order to calculate the mean and the sample deviation we can use the following formulas:

In order to calculate the critical value $t_{\alpha/2}$ we need to find first the degrees of freedom, given by:

$df=n-1=40-1=39$

Since the Confidence is 0.95 or 95%, the value of $\alpha=0.05$ and $\alpha/2 =0.025$ , and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.025,39)".And we see that $t_{\alpha/2}=2.02$

Now we have everything in order to replace into formula (1):

$52.8-2.02\frac{3.9}{\sqrt{40}}=51.554$

b) What is the upper limit of the 95% interval? Give your answer to three decimal places

$52.8+2.02\frac{3.9}{\sqrt{40}}=54.046$

So on this case the 95% confidence interval would be given by (51.554;54.046)

c) What is the lower limit of the 99% interval? Give your answer to three decimal places

Since the Confidence is 0.99 or 99%, the value of $\alpha=0.01$ and $\alpha/2 =0.005$ , and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.005,39)".And we see that $t_{\alpha/2}=2.71$

Now we have everything in order to replace into formula (1):

$52.8-2.71\frac{3.9}{\sqrt{40}}=51.129$

d) What is the upper limit of the 99% interval? Give your answer to three decimal places

$52.8+2.71\frac{3.9}{\sqrt{40}}=54.471$

So on this case the 99% confidence interval would be given by (51.129;54.471)

e) Consider the claim that the mean amount of garbage per bin is 54.1985 pounds. Is the following statement true or false? The decision about the claim would depend on whether we use a 95% or 99% confidence interval: True/False

Yes, depends of the confidence level.

At 95 % of confidence the value 54.1985 pounds is not included on the interval. At 5% of significance the statement is FALSE.

At 99 % of confidence the value 54.1985 pounds is included on the interval. So at 1% of significance the statement is TRUE.

3 0

3 years ago