calculate the magnitude of the electric field intensity in vacuum at a distance of 20 cm from a charge of 5 * 10 raise to power
1 answer:
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Answer:
0.15694 m
Explanation:
m = Mass of block =
v = Velocity of block = 11.2 m/s
k = Spring constant = 110 N/m
Here the kinetic energy of the fall and spring are conserved
The amplitude of the resulting simple harmonic motion is 0.15694 m
Answer: 1. h
Explanation:
The block would reach exactly the same height from the ground. It would travel a greater distance away from the source, but the height away from the earth would remain the same as you are giving it the same energy each time. Therefore, it will reach the same gravitation potential energy.
Another approach to look at it this is seeing it when the Block moves up the slope, its kinetic energy decreases and the potential energy increases. In both cases, the kinetic energy decreases by same amount, therefore the block rises to same height H.
Try to use the formula;
1/2MV2 = mgh
Where V = √(2gh)
I hope this helps
