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2 years ago

The idea that species change over time is called

Physics

2 answers:

Free_Kalibri [48]2 years ago

7 0

Evolution

hope this helps

qaws [65]2 years ago

4 0

The answer is evolution. When a specifies evolves over time they change and adapt to their environment.

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A giraffe is slowly walking across a field. Is it balanced or unbalanced?

vodka [1.7K]

Your answers are correct

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3 years ago

Car À moves at a speed of 8m/s for 43 seconds. Car B moves at a speed of 7 m/s for 50 seconds. Which car traveled a longer dista

nadezda [96]

Distance = (speed) x (time)

Car A: Distance = (8 m/s) x (43 s) = 344 meters

Car B: Distance = (7 m/s) x (50 s) = 350 meters

350 meters is a longer distance than 344 meters.

<em>Car-B traveled a longer distance</em> than Car-A did.

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2 years ago

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Gold has a higher density than tin? True or false

Ganezh [65]

Answer:

True. Gold does have a higher density than tin

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2 years ago

Plssssss look at the picture i need it right hurry pls

Karo-lina-s [1.5K]

Answer:

it is B

Explanation:

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2 years ago

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The flywheel of a steam engine runs with a constant angular velocity of 190 rev/min. When steam is shut off, the friction of the

Ivanshal [37]

Answer:

(a) $\alpha = - 1.32\ rev/m^{2}$

(b) $\theta = 13674\ rev$

(d) $a = 22.458\ m/s^{2}$

Solution:

As per the question:

Angular velocity, $\omega = 190\ rev/min$

Time taken by the wheel to stop, t = 2.4 h = $2.4\times 60 = 144\ min$

Distance from the axis, R = 38 cm = 0.38 m

Now,

(a) To calculate the constant angular velocity, suing Kinematic eqn for rotational motion:

$\omega' = \omega + \alpha t$

$omega'$ = final angular velocity

$\omega$ = initial angular velocity

$\alpha$ = angular acceleration

Now,

$0 = 190 + \alpha \times 144$

$\alpha = - 1.32\ rev/m^{2}$

Now,

(b) The no. of revolutions is given by:

$\omega'^{2} = \omega^{2} + 2\alpha \theta$

$0 = 190^{2} + 2\times (- 1.32) \theta$

$\theta = 13674\ rev$

(c) Tangential component does not depend on instantaneous angular velocity but depends on radius and angular acceleration:

$\alpha_{tan} = 0.38\times 1.32\times \frac{2\pi}{3600} = 8.75\times 10^{- 4}\ m/s^{2}$

(d) The radial acceleration is given by:

$\alpha_{R} = R\omega^{2} = 0.32(80\times \frac{2\pi}{60})^{2} = 22.45\ rad/s$

Linear acceleration is given by:

$a = \sqrt{\alpha_{R}^{2} + \alpha_{tan}^{2}}$

$a = \sqrt{22.45^{2} + (8.75\times 10^{- 4})^{2}} = 22.458\ m/s^{2}$

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2 years ago