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Neko [114]
3 years ago
15

A block is launched up a frictionless 40° slope with an initial speed v and reaches a maximum vertical height h. The same block

is launched up a frictionless 20° slope with the same initial speed v. On this slope, the block reaches a maximum vertical height of _____.
1. h
2. h/2
3. 2h
4. A height greater than h but less than 2h.
5. A height greater than hl2 but less than h.

Physics
1 answer:
Strike441 [17]3 years ago
3 0

Answer: 1. h

Explanation:

The block would reach exactly the same height from the ground. It would travel a greater distance away from the source, but the height away from the earth would remain the same as you are giving it the same energy each time. Therefore, it will reach the same gravitation potential energy.

Another approach to look at it this is seeing it when the Block moves up the slope, its kinetic energy decreases and the potential energy increases. In both cases, the kinetic energy decreases by same amount, therefore the block rises to same height H.

Try to use the formula;

1/2MV2 = mgh

Where V = √(2gh)

I hope this helps

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Answer: So they can find your mistakes that you made you skipped over

Explanation:

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4 years ago
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What energy transformation is involved in movement of muscles?
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8 0
3 years ago
A car of mass 900 kg is traveling at 20 m/s when the brakes are applied. The car then comes to a complete stop in 5 s. What is t
ollegr [7]

Answer:

A. 36,000 W

Explanation:

m = mass of the car = 900 kg

v_{o} = Initial speed of the car = 20 m/s

v_{f} = Final speed of the car = 0 m/s

W = Work done by the brakes on the car

Magnitude of work done on the car by the brakes is same as the change in kinetic energy of the car.hence

W = (0.5) m (v_{o}^{2} - v_{f}^{2})\\W = (0.5) (900) ((20)^{2} - (0)^{2})\\W = 180000 J

t = time taken by the car to come to stop = 5 s

P = Average power produced by the car

Average power produced by the car is given as

P = \frac{W}{t} =\frac{180000}{5} \\P = 36000 W

8 0
3 years ago
The index of refraction of silicate flint glass for red light is 1.620 and for violet light is 1.660 . A beam of white light in
chubhunter [2.5K]

Answer:

The angular separation equals 0.35^{o}

Explanation:

We have according to Snell's law

n_{1}sin(\theta _{1})=n_{2}sin(\theta _{2})

\therefore \theta _{2}=sin^{-1}(\frac{n_{1}sin(\theta _{1})}{n_{2}})

Using this equation for both the colors separately we have

\theta _{red}=sin^{-1}(\frac{sin(23.90^{o})}{1.62})\\\\\theta _{red}=14.48^{o}

Similarly for violet light we have

\theta _{violet}=sin^{-1}(\frac{sin(23.90^{o})}{1.660})\\\\\theta _{violet}=14.13^{o}

Thus the angular separation becomes

\Delta \theta =14.48-14.13=0.35^{o}

6 0
4 years ago
A car starts from rest and travels to the north for 6.00 s with a uniform acceleration of 2.50
Snowcat [4.5K]
To calculate the final velocity, we use Newton's first equation of linear motion:v=u+at
Where v is final velocity
u is initial velocity
a is the average acceleration
t is the time taken during acceleration.
Therefore,
v=0+2.5m/s²*6.00s
=15m/s
Decelerating from 15m/s;
v=15m/s+(-2m/s²×4.0s)
=3m/s To get the distance it travelled, we use v²=u²+2as During acceleration, the distance travelled is calculated as below. 15²=0+2×2.5S 225=5S S=45meters During decellaration, displacement is calculated as below, 3²=15²+(2×4S) 9=225+8S 8S=216 S=27meters Total displacement=45m+27m =72 meters.
7 0
3 years ago
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