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solmaris [256]
3 years ago
6

A triangle with all sides of equal length is a/an _______ triangle.

Mathematics
2 answers:
Vsevolod [243]3 years ago
7 0
Hello There!
____________________________________________________________

A triangle with all sides of equal length is a/an equilateral triangle
____________________________________________________________

Hope This Helps You!
Good Luck :) 
- Hannah ❤
vampirchik [111]3 years ago
6 0
The answer is an Equilateral triangle. 

In addition, all the interior angles are same too, which means its also equiangular. 

The most common 3 types of triangle classification on their length of sides include equilateral, isosceles, which means 2 sides have the same length, and scalene triangle, where 3 sides has different lengths. 

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heather writes the equations below to represent two lines drawn on the coordinate plane. –6x 18y = 0 4x – 12y = 20 after applyin
Tju [1.3M]

The <em><u>correct answer</u></em> is:

The equation has no solution; therefore, the system of equations has no solution.

Explanation:

When solving a system of equations, after we combine the equations, if we find that there is no solution, that means that there is no solution to the entire system of equations.

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3 years ago
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Max's Moving Company charges a $75 loading fee to move your boxes. They also charge $2 per mile that they have to drive the van
maks197457 [2]

Answer:

y=75+2x

Step-by-step explanation:

Given data

Loading fee=$75

Charge per mile= $2

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and the total charge be y

Hence the expression for the total charge is

y=75+2x

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3 years ago
As school prefect, write a letter to your District or municipal or metropolitan executive requesting the maintenance of the buil
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3 years ago
how do you rewrite : y=x^2-5x+9 in standard form using complying the square? I keep getting to : x^2-5x-25/4 but I’m not allowed
yawa3891 [41]

I presume with this you meant to say you want this equation in <u>general form</u>, also known as vertex form, which is y = a(x - h)² + k, instead of <u>standard form</u>, which is y = ax² + bx + c, which is what the original equation is already in.

So with completing the square, you first have to isolate the x-terms. To do this, subtract 9 on both sides of the equation:

y-9=x^2-5x

Next, we want to make the right side of the equation a perfect square. To find the constant of this soon-to-be perfect square, divide the x-coefficient by 2 and square that quotient. In this case:

-5\div 2 = -\frac{5}{2}\\\\(-\frac{5}{2})^2=-\frac{5}{2}\times-\frac{5}{2}=\frac{25}{4}

Now add 25/4 on both sides of the equation:

y-9+\frac{25}{4}=x^2-5x+\frac{25}{4}

Now to combine -9/1 and 25/4, they must have the same denominator, and to find it you must find the LCD, or lowest common denominator, of 1 and 4. To find it, list the multiples of both and the lowest one they share is their LCD. In this case, the LCD is 4. Multiply both sides of -9/1 by 4/4 and then add the numerators up:

-\frac{9}{1}\times \frac{4}{4}=-\frac{36}{4}\\\\-\frac{36}{4}+\frac{25}{4}=-\frac{11}{4}\\\\y-\frac{11}{4}=x^2-5x+\frac{25}{4}

Next, we need to factor the right side of the equation. Using this format of a^2-2ab+b^2=(a-b)^2 , we can factor it as:

y-\frac{11}{4}=(x-\frac{5}{2})^2

Now lastly, add both sides by 11/4, and <u>your final answer will be y=(x-\frac{5}{2})^2+\frac{11}{4}</u>

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