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Kamila [148]
3 years ago
7

The attendance at a seminar in 1 year was 500. in year 2, the attendance changed by 100. what was the percent change in the atte

ndance?
A.the percent change was 0.2%
B. the percent change was 0.4%
C. the percent change was 20%
D. the percent change was 40%
Mathematics
2 answers:
chubhunter [2.5K]3 years ago
6 0

Answer:

C

Step-by-step explanation:

500÷100=20%

since the change is 100 and the first amount is 500 we do 500÷100=20% which is the percentage it changed

Masja [62]3 years ago
3 0

Answer:

C

Step-by-step explanation:

100/500=0.2

0.2=20%

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Rylee shopped at a clothing store, where she spent $36.50 plus 8% tax. Then, she spent $25 to refuel her car at the gas station.
inn [45]

Answer: The net change to her banking account balance is $83.22.

Step-by-step explanation:

Hi to answer this question we have to analyze the information given:

She spent $36.50 plus 8% tax.  ( to calculate the tax amount we have to multiply the cost by the percentage in decimal form)

36.50 x (8/100) =$2.92 (value of tax)

Adding to the original cost

36.50+2.92 = $39.42

Then, she spent $25 to refuel her car at the gas station.

39.42 +25 = $64.42

She bought groceries worth $23.50. At the grocery checkout, she handed over a coupon for a 20% discount on her purchase

23.50 x (20/100) = 4.7 (amount of discount)

Subtracting to the purchase

23.50 -4.7= $18.8

Finally, adding to the total cost.

64.42 +18.8 = $83.22

4 0
3 years ago
Having trouble with this, help please? <br><br> I will give brainliest.
yaroslaw [1]

Answer:

a)     7x-15=20

b)   \frac{20+15}{7}

c)  5

Step-by-step explanation:

4 0
1 year ago
Answer and I will give you brainiliest ​
nekit [7.7K]

Answer:

40 is your correct answer

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2 years ago
Problem: Four students tried to write 12x + 3y=9 in equivalent y= mx + b form.
solmaris [256]

Answer:what grade is this

Step-by-step explanation:

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3 years ago
Read 2 more answers
Write the equation of a Line that is perpendicular to y=5/2x+3 and passes
koban [17]

Answer:

Step-by-step explanation:

Slope of perpendicular lines = -1

y = 5/2x + 3

m_{1}=\frac{5}{2}\\\\m_{1}*m_{2}=-1\\\\

        m_{2}= -1 ÷ m_{1}

               = -1*\frac{2}{5}=\frac{-2}{5}

(-3 , -5)

Equation of the required line: y - y₁ = m(x -x₁)

                                                y - [5] = \frac{-2}{5}(x - [-3])\\

                                               y+5=\frac{-2}{5}x + 3*\frac{-2}{5}\\\\y+5=\frac{-2}{5}x-\frac{6}{5}\\\\   y =\frac{-2}{5}x-\frac{6}{5}-5\\\\   y = \frac{-2}{5}x-\frac{6}{5}-\frac{5*5}{1*5}\\\\ y = \frac{-2}{5}x-\frac{6}{5}-\frac{25}{5}\\\\\\ y=\frac{-2}{5}x-\frac{31}{5}

5 0
3 years ago
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