$x^2+5x-9\\\\a=1;\ b=5;\ c=-9\\\Delta=b^2-4ac\\\\\Delta=5^2-4\cdot1\cdot(-9)=25+36=61 > 0\\\\x_1=\dfrac{-b-\sqrt\Delta}{2a}\ and\ x_2=\dfrac{-b+\sqrt\Delta}{2a}\\\\\sqrt\Delta=\sqrt{61}\\\\x_1=\dfrac{-5-\sqrt{61}}{2\cdot1}=\dfrac{-5-\sqrt{61}}{2}\\\\x_2=\dfrac{-5+\sqrt{61}}{2\cdot1}=\dfrac{-5+\sqrt{61}}{2}\\\\x^2+5x-9=\left(x-\dfrac{-5-\sqrt{61}}{2}\right)\left(x-\dfrac{-5+\sqrt{61}}{2}\right)$

6 0

2 years ago

Are these equivalent?

evablogger [386]

Answer:

Step-by-step explanation:

4 x 2 = 14

<u><em>BUT</em></u>

3 x 2 ≠ 9

4 0

3 years ago

Read 2 more answers

What is the answer for 23x9+(91+7)

mestny [16]

Answer:

305

Step-by-step explanation:

23×9+98

207+98

305

3 0

3 years ago

Read 2 more answers