Answer:
Option D is the correct answer.
Step-by-step explanation:
Let x be the one way distance and t be the time out.
Time taken for back = t-1
We have plane's average speed out was 300 mph and average speed on the way back was 350 mph.
That is

Dividing both equations

Time taken for back = t-1 = 7-1 = 6 hours.
Total time taken = 7 + 6 = 13 hours
Option D is the correct answer.
The probability that the train will be there when Alex arrives is 5/18
If Alex arrives at any time after 1.20pm the chances that train will be there is 1/3.
However if alex arrives at 1.00pm exactly there is no chance the train will be arrive there.
The probability that the train will be there increase linearly to 1/3 as alex's arrival time moves from 1.00pm to 1.20pm.
By arranging the probabilities over the first 20 minutes to get a 1/6 chance the train will be there if alex arrives between 1.00pm to 1.20pm
we get the final answer by
=1/3( 1/6 + 1/3 + 1/3)
=5/18
So, the probability that the train will be there when Alex arrives is 5/18
Learn more about PROBABILITY here
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move the decimal point 2 places to the left
42.6 /
= 0.426
Answer:
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