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natka813 [3]
3 years ago
8

Use the greatest common factor and the distributive property to write and an equivalent expression: 20g+24h

Mathematics
1 answer:
n200080 [17]3 years ago
4 0
4(5g+6h)

You xan remove four from each number, but no letters since they dont have any of the same.
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Find the whole amount in each case <br> 32% is 64 mL.
REY [17]

Answer:

It's 200 ml I believe.

Step-by-step explanation:

8 0
2 years ago
Find the distance between (-2, 8) and (11, 2). Round to the nearest hundredth.
andrew11 [14]

Answer: 14.32 units

Step-by-step explanation:

The formula for calculate the distance between two points is:

d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

In this case, given the points (-2,8) and (11,2), we can identify that:

x_2=11\\x_1=-2\\\\y_2=2\\y_1=8

Therefore, we just need to substitute values into the formula in order to calculate the distance between the given points. This is (Rounded to the nearest hundred):

d=\sqrt{(11-(-2))^2+(2-8)^2}\\\\d=14.32\ units

7 0
3 years ago
ZA and ZB are supplementary angles. If m_A
KatRina [158]

Answer:

∠A = 107

∠B = 73

Step-by-step explanation:

∠A ,  ∠B are supplementary. So, ∠A + ∠B = 180

5x + 27 + 5x - 7 = 180

5x + 5x  + 27 - 7 = 180       {Combine like terms}

             10x + 20=180

                    10x = 180 -20

                   10x = 160

                      x = 160/10

x = 16

∠A = 5x + 27 = 5*16 + 27 = 80 + 27 = 107

∠B = 5x - 7 = 5*16 - 7 = 80 - 7 = 73

5 0
3 years ago
Can someone make me a
amm1812

Linear: y=3x-5

Non-Linear: y=x^2+3x+7

6 0
3 years ago
Read 2 more answers
7^16/7^12=7^-18/? what is the missing denominator
creativ13 [48]
\bf \left.\qquad \qquad \right.\textit{negative exponents}\\\\&#10;a^{-{ n}} \implies \cfrac{1}{a^{ n}}&#10;\qquad \qquad&#10;\cfrac{1}{a^{ n}}\implies a^{-{ n}}&#10;\qquad \qquad &#10;a^{{{  n}}}\implies \cfrac{1}{a^{-{{  n}}}}\\\\&#10;-------------------------------\\\\

\bf \cfrac{7^{16}}{7^{12}}=\cfrac{7^{-18}}{x}\implies x\cdot 7^{16}=7^{12}\cdot 7^{-18}\implies x\cdot 7^{16}=7^{12-18}&#10;\\\\\\&#10;x\cdot 7^{16}=7^{-6}\implies x=\cfrac{7^{-6}}{7^{16}}\implies x=\cfrac{7^{-6}\cdot 7^{-16}}{1}\implies x=7^{-6-16}&#10;\\\\\\&#10;\boxed{x=7^{-22}}\implies x=\cfrac{1}{7^{22}}
4 0
3 years ago
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