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natka813 [3]
3 years ago
8

Use the greatest common factor and the distributive property to write and an equivalent expression: 20g+24h

Mathematics
1 answer:
n200080 [17]3 years ago
4 0
4(5g+6h)

You xan remove four from each number, but no letters since they dont have any of the same.
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#2, can someone help me with this question?
Greeley [361]

Answer:

166.5 m³

Step-by-step explanation:

Vcone = ⅓ × pi × r² × h

pi × r² × h = 3 × Vcone

Vcylinder = pi × r² × h

Vcylinder = 3 × Vcone

Vcylinder = 3 × 55.5 = 166.5 m³

8 0
3 years ago
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What value of m makes the equation true? m + 2m - 6 = -12 + 2m.
denpristay [2]

the answer is 6 i think

4 0
3 years ago
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The area of the floor is 6,175 square feet. The length of the floor is 95 feet. The width is w feet.
Anestetic [448]

Answer:

the width is 65

Step-by-step explanation:

width x length = area

w x 95 = 6,175

6,175 / 95 = 65

65 x 95 = 6175

3 0
3 years ago
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A student records the number of hours that they have studied each of the last 23 days. They compute a sample mean of 2.3 hours a
natita [175]

Answer:

the standard deviation increases

Step-by-step explanation:

Let x₁ , x₂, .   .   .  , x₂₃ be the actual data observed by the student

The sample means  = x₁  +  x₂  +  .   .   .  , x₂₃ / 23

= \frac{x_1 +x_2 +...x_2_3}{23}

= 2.3hr

⇒\sum xi =2.3 \times 23 = 52.9hrs

let x₁ , x₂, .   .   .  , x₂₃  arranged in ascending order

Then x₂₃ was 10  and has been changed to 14

i.e x₂₃ increase to 4

Sample mean  = \frac{x_1 +x_2 +...x_2_3}{23}

\frac{52.9hrs + 4}{23} \\\\= \frac{56.9}{23} \\\\= 2.47

therefore, the new sample mean is 2.47

2) For the old data set

the median is x_1_2(th) values

[\frac{n +1}{2} ]^t^h value

when we use the new data set only x₂₃ is changed to 14

i.e the rest all observation remain unchanged

Hence, sample median = [{x_1_2]^t^h value remain unchange

sample median = 2.5hrs

The Standard deviation of old data set is calculated

=\sqrt{\frac{1}{n-1} \sum (xi - \bar x_{old})^2 } \\\\=\sqrt{\frac{1}{22}\sum ( xi - 2.3)^2 }---(1)

The new sample standard sample deviation is calculated as

= \sqrt{\frac{1}{n-1} \sum (xi-2.47)^2} ---(2)

Now, when we compare (1) and (2)  the square distance between each observation xi and old mean is less than the squared distance between each observation xi and the new mean.

Since,

(xi - 2.3)²  ∑ (xi - 2.47)²

Therefore , the standard deviation increases

6 0
3 years ago
2.) A cubic function that has 3 zeros: 2, -5, and 7.
stiv31 [10]

Answer:

65

Step-by-step explanation:

8 0
3 years ago
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