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mamaluj [8]
3 years ago
8

4) When carbon disulfide burns in the presence of oxygen, sulfur dioxide and carbon

Chemistry
1 answer:
Mars2501 [29]3 years ago
8 0

Answer:

94.6% yield

Explanation:

25.0 g CS2 (\frac{1 mol CS2}{76 g CS2}) (\frac{2 mol SO2}{1 mol CS2} ) (\frac{64 g SO2}{1 mol SO2} ) = 42.8 g SO2

42.8 g SO2  -> 100% yield

40.5 g SO2  -> x

x= (40.5 g SO2 * 100)/42.8 g SO2     x=94.6%

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