Question

4) When carbon disulfide burns in the presence of oxygen, sulfur dioxide and carbon

Answer 1

Answer:

94.6% yield

Explanation:

$25.0 g CS2 (\frac{1 mol CS2}{76 g CS2}) (\frac{2 mol SO2}{1 mol CS2} ) (\frac{64 g SO2}{1 mol SO2} ) = 42.8 g SO2$

42.8 g SO2  -> 100% yield

40.5 g SO2  -> x

x= (40.5 g SO2 * 100)/42.8 g SO2     x=94.6%