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3 years ago

4) When carbon disulfide burns in the presence of oxygen, sulfur dioxide and carbon

Chemistry

1 answer:

Mars2501 [29]3 years ago

8 0

Answer:

94.6% yield

Explanation:

$25.0 g CS2 (\frac{1 mol CS2}{76 g CS2}) (\frac{2 mol SO2}{1 mol CS2} ) (\frac{64 g SO2}{1 mol SO2} ) = 42.8 g SO2$

42.8 g SO2 -> 100% yield

40.5 g SO2 -> x

x= (40.5 g SO2 * 100)/42.8 g SO2 x=94.6%

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Evgen [1.6K]

Answer:

4) the one that is reduced, which is the oxidizing agent

Explanation:

An oxidizing agent is one that causes oxidation by gaining electrons from another atom/molecule.

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3 years ago

A student fails to clean the pipet first. after delivering the vinegar sample, the student notices a drop of vinegar clinging to

VladimirAG [237]

This should not matter because the pipet has gradations and usually more of the sample is taken up in the pipette than what is delivered into the flask the student should always rinse the container being used because they are contaminating the sample if they do not clean it out

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3 years ago

How many grams of Ca(NO3)2 are needed to make 25.0 g of a 15.0% Ca(NO3)2(aq)?

yarga [219]

Answer:

3.75 g.

Explanation:

mass percent is the ratio of the mass of the solute to the mass of the solution multiplied by 100.

mass % = (mass of solute/mass of solution) x 100.

mass of calcium nitrite = ??? g,

mass of the solution = 25.0 g.

∴ mass % = (mass of solute/mass of solution) x 100

∴ mass of solute (calcium nitrite) = (mass %)(mass of solution)/100 = (15.0 %)(25.0 g)/100 = 3.75 g.

5 0

3 years ago

PLEASE HELP ASAP !!

Ivenika [448]

Answer:

2SO₂ + O₂ + 2H₂O -----------> 2H₂SO₄

Theoretical yield of H₂SO₄ = 213 g

percent yield of H₂SO₄ = 94 %

Explanation:

Data Given:

volume of SO₂ = 48.6 L

mass of H₂SO₄ = 200 g

balance equation = ?

theoretical yield = ?

percent yield = ?

Solution:

Part 1:

first we have to write a balance equation for the reaction

SO₂ gas react with water (H₂O) and excess oxygen

The balanced equation is as under

2SO₂ + O₂ + 2H₂O -----------> 2H₂SO₄

Part 2:

Now we have to find theoretical yield

First look at the balance reaction

2SO₂ + O₂ + 2H₂O -----------> 2H₂SO₄

2 mol 2 mol

2 moles of SO₂ give gives 2 moles of H₂SO₄

Now calculate volume of 2 moles of SO₂ and mass of 2 moles of H₂SO₄

volume of 2 moles of SO₂

Formula used

volume of gas = no. of moles x molar volume . . . . . . (1)

molar volume of SO₂= 22.4 L/mol

Put values in above formula (1)

volume of gas = 2 mol x 22.4 L/mol

volume of gas = 44.8 L

volume of 2 mole of SO₂ = 44.8 L

Now,

Find mass of 2 mole H₂SO₄

Formula Used

mass in grams = no. of moles x molar mass . . . . . . . (2)

molar mass of H₂SO₄ = 2 (1) + 32 + 4(16)

molar mass of H₂SO₄ = 98 g/mol

put values in equation 2

mass in grams = 2 mol x 98 g/mol

mass in grams = 196 g

mass of 2 mole of H₂SO₄ = 196 g

** So,

Now we come to know that

44.8 L of SO₂ gives 196 g of H₂SO₄ then how many grams of the H₂SO₄ will be produced by 48.6 L of SO₂

Apply unity Formula

44.8 L of SO₂ ≅ 196 g of H₂SO₄

48.6 L of SO₂ ≅ X g of H₂SO₄

Do cross multiplication

g of H₂SO₄ = 196 g x 48.6 L / 44.8 L

g of H₂SO₄ = 213 g

So that is why the theoretical yield of H₂SO₄ is 213 g

Theoretical yield of H₂SO₄ = 213 g

Part 3

Calculate Percent Yield:

Formula used for this purpose:

percent yield = actual yield /theoretical yield x 100 %

Put value in the above formula

percent yield = 200 g/ 213 g x 100 %

percent yield = 94 %

So percent yield of H₂SO₄ = 94 %

8 0

3 years ago

In the following reaction, how many grams of nitroglycerin C3H5(NO3)3 will decompose to give 25 grams of CO2?

gogolik [260]

4C₃H₅(NO₃)₃ $_{(l)}$ ------> 12CO₂ $_{(g)}$ + 6N₂ $_{(g)}$ + 10H₂O $_{(g)}$ + O₂ $_{(g)}$

mol of CO₂ = $\frac{mass}{molar mass}$

= $\frac{25g}{44.01 g/mol}$

mol ratio of CO₂ : C₃H₅(NO₃)₃

12 : 4

∴ if mole of CO₂ = 0.568 mol

then " " C₃H₅(NO₃)₃ = $\frac{0.568 mol}{12} * 4$

= 0.189 mol

∴ mass of nitroglycerin = mole * Mr

= 0.189 mol * 227.0995 g / mol

= 43.00 g

8 0

3 years ago