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Ludmilka [50]
3 years ago
9

In a laboratory demonstration, a balloon filled with methane and oxygen was exposed to a flame. The result was a brief, large fl

ame. The students were asked to formulate an equation for the reaction. One answer is below. (3 points) Is this equation correct? Explain your reasoning.
Chemistry
1 answer:
adell [148]3 years ago
6 0

Answer:

CH4(g) + 2O2(g) -------> CO2(g) + 2H2O(g)

Explanation:

Even though the question is incomplete because the equations are missing. However, one thing that is clear from the question is that the reaction is a combustion reaction.

A combustion reaction is a type of reaction that produces heat and light. The mixture of methane and oxygen yielded a brief, large flame which shows that combustion has taken place according to the equation shown above.

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Answer:

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Explanation:

molar mass of Fe = 55.845g

to find moles = mass/ molar mass

so moles of Fe = 20/55.845

= 0.358 moles

for the equation you are given

for every three Fe, it produces 1 Fe3O4 , meaning the ratio is 3:1

if you have 0.358 moles of Fe, that means the number of moles of Fe3O4  will equal to one third of that,

thus

moles of Fe3O4 = 1/3 x 0.358 = 0.119

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