When the valve between the two containers is opened and the gases allowed to mix, how does the volume occupied by the n2 gas cha
nge? express your answer using two significant figures?
2 answers:
The volume occupied by the N₂ gas change : <u>5 L</u>
<h3>Further explanation </h3>There are several gas equations in various processes:
- 1. The ideal ideal gas equation
PV = NkT
N =number of gas particles
n = number of moles
R = gas constant (8,31.10 ^ 3 J / kmole K
k = Boltzmann constant (1,38.10 ^ -23)
n = = N / No
n = m / m
n = mole
No = Avogadro number (6.02.10 ^ 23)
m = mass
M = relative molecular mass
- 2. Avogadro's hypothesis
In the same temperature and pressure, in the same volume conditions, the gas contains the same number of molecules
So it applies: the ratio of gas volume will be equal to the ratio of gas moles
<h3> V1: V2 = n1: n2 </h3>
- 3. Boyle's Law
At a fixed temperature, the gas volume is inversely proportional to the pressure applied
<h3> p1.V1 = p2.V2 </h3>
- 3. Charles's Law
When the gas pressure is kept constant, the gas volume is proportional to the temperature
<h3> V1 / T1 = V2 / T2 </h3>
- 4. Gay Lussac's Law
When the volume is not changed, the gas pressure in the tube is proportional to its absolute temperature
<h3> P1 / T1 = P2 / T2 </h3>
- 5. Law of Boyle-Gay-Lussac
Combined with Boyle's law and Gay Lussac's law
P1.V1 / T1 = P2.V2 / T2
P1 = initial gas pressure (N / m2 or Pa)
V1 = initial gas volume (m3)
P2 = gas end pressure
V2 = the final volume of gas
T1 = initial gas temperature (K)
T2 = gas end temperature
From the attached picture, it shows that if the stopvalve is opened then the two gas systems / containers will be interconnected (almost the same as the related vessel system). So that the total volume filled by the two gases (O₂ and N₂) becomes:
total volume = O₂ container volume + N₂ container volume
total volume = 3 L + 2 L
total volume = 5 L
<h3>Learn more </h3>
a description of Charles’s law
Charles's law
State Boyle's, Charles's, and Gay-Lussac's laws
Keywords: containers, valve, O₂, N₂, volume, gas
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Answer:
37 %.
Explanation:
¡Hola!
En este caso, para el problema descrito, conocemos la corriente de entrada y la de salida del agua, por lo que podemos obtener el flujo de la corriente que contiene el zumo a la salida una vez el agua fue evaporada:
Luego, por medio de un balance de zumo de limón en el evaporador en el cual la cantidad que entra es igual a la que sale con sus respectivas concentraciones:
Como la concentración del zumo a la salida es del 50 % (0.50), la de entrada es:
Que es igual al 37%.
¡Saludos!