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ArbitrLikvidat [17]
3 years ago
11

When the valve between the two containers is opened and the gases allowed to mix, how does the volume occupied by the n2 gas cha

nge? express your answer using two significant figures?

Chemistry
2 answers:
schepotkina [342]3 years ago
4 0
Missing question: 
Nitrogen: <span>2.0 L; </span>1.0 atm; 25°<span>C.
Oxygen: 3</span>.0 L; 2.0 atm; 25°C.
<span>When the valve between the two containers is opened, nitrogen gas moves from one container to another container and gases are mixed together, total volume of nitrogen is than:
V(nitrogen) = 2,0 L + 3,0 L = 5,0 L.</span>
sertanlavr [38]3 years ago
3 0

The volume occupied by the N₂ gas change : <u>5 L</u>

<h3>Further explanation </h3>

There are several gas equations in various processes:

  • 1. The ideal ideal gas equation
<h3>PV = nRT </h3>

PV = NkT

N =number of gas particles

n = number of moles

R = gas constant (8,31.10 ^ 3 J / kmole K

k = Boltzmann constant (1,38.10 ^ -23)

n = = N / No

n = m / m

n = mole

No = Avogadro number (6.02.10 ^ 23)

m = mass

M = relative molecular mass

  • 2. Avogadro's hypothesis

In the same temperature and pressure, in the same volume conditions, the gas contains the same number of molecules

So it applies: the ratio of gas volume will be equal to the ratio of gas moles

<h3> V1: V2 = n1: n2 </h3>

  • 3. Boyle's Law

At a fixed temperature, the gas volume is inversely proportional to the pressure applied

<h3> p1.V1 = p2.V2 </h3>

  • 3. Charles's Law

When the gas pressure is kept constant, the gas volume is proportional to the temperature

<h3> V1 / T1 = V2 / T2 </h3>

  • 4. Gay Lussac's Law

When the volume is not changed, the gas pressure in the tube is proportional to its absolute temperature

<h3> P1 / T1 = P2 / T2 </h3>

  • 5. Law of Boyle-Gay-Lussac

Combined with Boyle's law and Gay Lussac's law

P1.V1 / T1 = P2.V2 / T2

P1 = initial gas pressure (N / m2 or Pa)

V1 = initial gas volume (m3)

P2 = gas end pressure

V2 = the final volume of gas

T1 = initial gas temperature (K)

T2 = gas end temperature

From the attached picture, it shows that if the stopvalve is opened then the two gas systems / containers will be interconnected (almost the same as the related vessel system). So that the total volume filled by the two gases (O₂ and N₂) becomes:

total volume = O₂ container volume + N₂ container volume

total volume = 3 L + 2 L

total volume = 5 L

<h3>Learn more </h3>

a description of Charles’s law

brainly.com/question/5056208

Charles's law

brainly.com/question/9510865

State Boyle's, Charles's, and Gay-Lussac's laws

brainly.com/question/980439

Keywords: containers, valve, O₂, N₂, volume, gas

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Calcium chloride = CaCl2

Ionization equation: CaCl2 ---> Ca (2+) + 2 Cl (-)

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Calculate the number of moles of CaCl2 in 1.5 liters of 5.5 * 10^-2 M solution

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number of moles of Mg(NO3)2 in 1.5 liter of 8.0 * 10^-2 M solution

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ions of Mg(2+) = 0.12 mol Mg(NO3)2 * 1 mol Mg(2+) / mol Mg(NO3)2 = 0.12 mol Mg(2+)

4) Number of phosphate ions needed to react with 0.12 mol Mg(2+)

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=> 2 mol PO4(3-) / 3 mol Mg(2+) = x / 0.12 mol Mg(2+)

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=> 1 mol Na3PO4 : 1 mol PO4(3-)

=> 0.215 mol PO4(3-) : 0.215 mol Na3PO4

mass in grams = number of moles * molar mass

molar mass of Na3 PO4 = 3*23 g/mol + 31 g/mol + 4*16 g/mol = 164 g/mol

=> mass in grams = 0.215 mol * 164 g/mol = 35.26 g

Answer: 35.26 g of sodium phosphate
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