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maria [59]
3 years ago
11

Question 1.1. Choose the correct answer.

Mathematics
2 answers:
faltersainse [42]3 years ago
5 0
I believe Nancy bought 45 Angelfish and 315 Goldfish. 360 / 8 = 45, 360-45=315
Yuki888 [10]3 years ago
3 0

the answer is 40 angelfish and 320 goldfish

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Leon drove 100 miles in 2 hours. Find the constant of variation.
Helga [31]

To find the constant variation, solve for only one hour (in this case).

Divide 100 with 2

100/2 = 50/1

Each hour is 50 miles driven, so your constant variation is 50 mph

3 0
3 years ago
Read 2 more answers
Write an equation for the parabolla
pentagon [3]

well, is noteworthy that an x-intercept is when y = 0 or namely is a solution or root of the quadratic, so we know then that the x-intercepts or solutions are at (-1,0) and (3,0), that simply means that

\bf (\stackrel{x}{-1},\stackrel{y}{0})\qquad (\stackrel{x}{3},\stackrel{y}{0})\qquad \begin{cases} x = -1\\ x+1=0\\ \cline{1-1} x=3\\ x-3=0 \end{cases}~\hfill \implies ~\hfill \stackrel{\textit{equation of the parabola}}{y = a(x+1)(x-3)} \\\\\\ \textit{we also know that } \begin{cases} x = 1\\ y = -8 \end{cases}\implies \underline{-8}=a(\underline{1}+1)(\underline{1}-3)

\bf -8=a(2)(-2)\implies -8=-4a\implies \cfrac{-8}{-4}=a\implies \boxed{2=a} \\\\[-0.35em] ~\dotfill\\\\ y=2(x+1)(x-3)\implies y=2(\stackrel{\mathbb{FOIL}}{x^2-2x-3})\implies y=2x^2-4x-6

4 0
3 years ago
Gary's car travel 30 miles on 1 1/5 gallon of gas. Gary wants to travel 90 miles. How many gallons of gas will his car use?
3241004551 [841]
Gary car will use 18 miles/gallons
7 0
3 years ago
Which is NOT a factor of 48?<br> A.24<br> B.16<br> C.4<br> D.26
vovikov84 [41]
26
Hope this was helpful !
4 0
3 years ago
Read 2 more answers
Write the terms a 1a1​, a 2a2​, a 3a3​, and a 4a4 of the following sequence. If the sequence appears to​ converge, make a conjec
Arturiano [62]

Answer:

Step-by-step explanation:

WE are given that a_n = \frac{(-1)^{n+1}}{5n-4}. Then, to now the first for terms, we must replace n by 1,2,3,4 respectively. Then

a_1 = \frac{(-1)^2}{5(1)-4} = \frac{1}{1}= 1

a_2 = \frac{(-1)^3}{5(2)-4} = \frac{-1}{6}

a_3 = \frac{(-1)^4}{5(3)-4} = \frac{1}{11}= 1

a_4 = \frac{(-1)^5}{5(4)-4} = \frac{-1}{16}= 1

Note that as n increase, a_n gets closer to 0. So, the limit of this sequence is 0.

6 0
3 years ago
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