Answer:
Probability that the diameter of a selected bearing is greater than 111 millimeters is 0.1056.
Step-by-step explanation:
We are given that the diameters of ball bearings are distributed normally. The mean diameter is 106 millimeters and the standard deviation is 4 millimeters.
<em>Firstly, Let X = diameters of ball bearings</em>
The z score probability distribution for is given by;
Z =
~ N(0,1)
where,
= mean diameter = 106 millimeters
= standard deviation = 4 millimeter
Probability that the diameter of a selected bearing is greater than 111 millimeters is given by = P(X > 111 millimeters)
P(X > 111) = P(
>
) = P(Z > 1.25) = 1 - P(Z
1.25)
= 1 - 0.89435 = 0.1056
Therefore, probability that the diameter of a selected bearing is greater than 111 millimeters is 0.1056.
Answer:

Step-by-step explanation:

Answer:
x=7 and y= 1/3
Step-by-step explanation:
we have -5x - 15 = -30 <=> x + 3 = 10
x= 7
if x=7
so 2×7 - 6y = 12 <=> 14 - 12 = 6×y
2 = 6y
y= 2/6 = 1/3
Answer: It would be between 7 and 8
Answer:
Option c.
Step-by-step explanation:
Using the normal curve to approximate a sampling distribution:
For a sample size n and a proportion n, the normal curve can be used if:
and 
Option a:


So option a cannot be used.
Option b:


So option b cannot be used.
Option c:


So option c can be used, and is the answer
Option d:


So option d cannot be used.
The answer is given by option c.