Answer:
You can just cancel out on both sides and find the value of the variable.
e.
5^0 = 1; 5^1 = 5; 5^2 = 25; 5^(-1) = 1/5; 5^(-2) = 1/25
This is an exponential function since the exponent is a variable.
Function: f(x) = 5^x
Recursive:
f.
Look at f(x) = x^2 for x = -2, -1, 0, 1, 2
f(-2) = 4
f(-1) = 1
f(0) = 0
f(1) = 1
f(2) = 2
Now look at the y-values in the table. They are the same we have here added to 5.
Your function is a quadratic function.
f(x) = x^2 + 5
I hope this helps you
6y-2x=20
2 (3y-x)=2.10
3y-x=10
3y=x+10
y=x+10/3
The function f(x)=x²
The vertex of the f(x) is at (0,0)
The vertex of the g(x) is at (0+7;0+5)=(7;5)
x(p)=7, y(q)=5
The vertex form of a quadratic equation is y = a(x -p)² + q, where (p, q) are the x- and y-coordinates of the vertex:


The answer:

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