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Luden [163]
3 years ago
15

What are the solutions to the equation 3(x – 4)(x + 5) = 0?

Mathematics
2 answers:
vesna_86 [32]3 years ago
7 0
First you distribute the 3
(3x-12) (x+5)=0
then you set each equation equal to zero
3x-12=0 & x+5=0
then you solve for x
x =4, -5
allochka39001 [22]3 years ago
4 0

Answer:

-5, 4

Step-by-step explanation:

the solutions to the equation 3(x - 4)(x + 5) = 0

To solve for x we set each factor =0 and solve for x

3(x-4)=0

divide each term by 3

(x-4)=0

Add 4 on both sides

x=4

x+5=0

Subtract 5 on both sides

x=-5

So x values are -5 and 4

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If m < 0 and b > 0, the graph of y = mx + b does not pass through which quadrant?
stiks02 [169]

Answer:

Quadrant III


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The attached picture shows graph of 4 such linear functions with the conditions given in the problem. ALL of them DO NOT pass through Quadrant III.

The graphs shown are of the functions:

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Answer:

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<em>P.S. Hope it makes sense. If you have any questions, feel free to share them in the comment senction below. I'll be happy to help. Have a wonderful day!</em>

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