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3 years ago

Given:

Mathematics

1 answer:

ale4655 [162]3 years ago

4 0

Plug in point values into the distance formula
*square root of* (-9+4)^2 + (0+8)^2
d≈ 9.4
step by step shown in picture

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What is the median of those in the the picture please help

Molodets [167]

Answer:

Median is 24.5

Step-by-step explanation:

Median is the middle number in a set of numbers. If we have two middle numbers, we get the average. And from the question, listing them out, we have this

0,1, 2, 3,4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20, 21, 22, 23, 24, 25, 26, 27, 28, 29, 30, 31, 32, 33, 34, 35, 36, 37, 38, 39, 40, 41, 42, 43, 44, 45, 46, 47, 48, 49.

The middle number here is 24 and 25. Getting their average will be 24.5

5 0

3 years ago

169= (24/2)^2 +(d/2)^2

OlgaM077 [116]

Answer: d = ±10

<u>Step-by-step explanation:</u>

169 = $(\frac{24}{2})^{2}$ + $(\frac{d}{2})^{2}$

169 = (12)² + $\frac{d^{2}}{4}$

169 = 144 + $\frac{d^{2}}{4}$

25 = $\frac{d^{2}}{4}$

100 = d²

√100 = √d²

±10 = d

6 0

3 years ago

Karl set out to Alaska on his truck. The amount of fuel remaining in the truck's tank (in liters) as a function of distance driv

Stells [14]

Answer:

500 kilometers

Step-by-step explanation:

The fuel (y) Karl has in his car is a function of the distance (x) Karl travelled. The amount of fuel (y) is dependent on the distance (x) Karl travelled.

On the y-axis, we have amount of fuel.

On the x-axis, we have distance travelled.

At the time Karl travelled when he had 200 liters of fuel (y) remaining in his car, he had travelled a distance (x) of 500 kilometers.

We know this by looking at the graph given. When x (distance) = 500, y (fuel) = 200.

6 0

3 years ago

The radius of a sphere is 6 units.

Rasek [7]

Answer:

choice 2) 4/3πr³

Step-by-step explanation:

5 0

2 years ago

Es 18 de junio de 1815, las tropas napoleónicas se encuentran justo adelante, tu eres el ingeniero en balística y el general Wel

Airida [17]

Answer:

89.1° or -1.4°

Step-by-step explanation:

1. Location:

You are on the Mont-Saint-Jean escarpment, near the Belgian town of Waterloo.

The French troops are about 50 m below you and 1.2 km distant.

2. Finding the firing angle

Data:

R = 1200 m

u = 600 m/s

h = -50 m (the height of the target)

a = 9.8 m/s²

We have two conditions.

Horizontal distance

(1) 1200 = 600t cosθ

Vertical distance

(2) -50 = 600t sinθ - 4.9t²

Divide each side of (1) by 600cosθ.

$(3) \, t =\dfrac{2}{\cos \theta}$

Substitute (3) into (2)

$-50 = 600t \sin \theta - 4.9t^{2} = 600 \left( \dfrac{2}{\cos \theta} \right ) \sin \theta - 4.9 \left( \dfrac{2}{\cos \theta} \right )^{2}\\\\(4) \, -50 = 1200 \tan \theta - \dfrac{19.6}{\cos^{2} \theta}$

Recall that

(5) sec²θ = 1/cos²θ = tan²θ + 1

Substitute (5) into (4)

$-50 = 1200 \tan \theta - 19.6 \left(\tan^{2} \theta}+ 1\right )$

Set up a quadratic equation

$\begin{array}{rcl}-50 & = & 1200 \tan \theta - 19.6\tan^{2} \theta -19.6 \\0 & = & 1200 \tan \theta - 19.6\tan^{2} \theta + 30.4\\0 & =&19.6\tan^{2} \theta - 1200 \tan \theta - 30.4\\0 & =&\tan^{2} \theta - 61.224 \tan \theta - 1.551\\\end{array}$

Solve for θ

Use the quadratic formula.

tanθ = 61.249 or -0.025

θ = arctan(61.249) = 89.1° or

θ = arctan(-0.025) = -1.4°

3 0

3 years ago