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3 years ago

Given:

Mathematics

1 answer:

ale4655 [162]3 years ago

4 0

Plug in point values into the distance formula
*square root of* (-9+4)^2 + (0+8)^2
d≈ 9.4
step by step shown in picture

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A company charges a shipping fee that is 4% of the purchase price for all items

Readme [11.4K]

4 percent of 66
0.04 = 4 percent
66 * 0.04 = 2.64
The shipping fee is $2.64

7 0

3 years ago

BRAINLIEST!!! 18. Point p is chosen at random on EH. Find the probability that p is on FG.

shepuryov [24]

Answer:

$\frac{2}{5}$

Step-by-step explanation:

The total length of this line is 15 units. FG is 6 units long.

This means that the probability of p being on FG would be $\frac{6}{15}$ which can be simplified to $\frac{2}{5}$

5 0

3 years ago

Read 2 more answers

Expand. Your answer should be a polynomial in standard form. (x2+4)(x2−6)=(x^2+4)(x^2-6)=(x2+4)(x2−6)=

Dafna11 [192]

Answer:

x^4 -2x^2 -24

Step-by-step explanation:

(x^2+4)(x^2−6)

FOIL

First: x^2*x^2 = x^4

Outer: x^2 *-6 = -6x^2

Inner: x^2 *4 = 4x^2

Last: 4*-6 = -24

Add them together

x^4 -6x^2 +4x^2 -24

Combine like terms

x^4 -2x^2 -24

This is in standard form since the powers decrease

8 0

3 years ago

Read 2 more answers

What is the mass of an object if it takes a net force of 32 N to accelerate

Sonbull [250]

We will find the answer using the second law of motion i.e. Force is equal to the product of mass and acceleration.

$\sf \: F=ma$

Where,

F is force
M is mass
A is acceleration

In our case,

F = 32 N
A = 0.88m/s
M = ?

Let's solve for M ~

$\tt \: 32 = m \times 0.88$

$\tt \: 32 = 0.88m$

$\tt \: 0.88m = 32$

$\tt \: m = 36.36$

Thus, The mass of object is 36.36 grams...~

5 0

2 years ago

Imagine that you have developed a genetic test to detect the dominant allele (A) that cause a rare genetic condition. As with mo

s344n2d4d5 [400]

Answer:

Correct option: (B) 1.495%.

Step-by-step explanation:

Denote the events as follows:

X = the test is positive.

A = a person with the dominant allele

The information given are:

$P(X|A)=1\\P (X|A^{c})=0.005\\P(A)=0.01$

According to the law of total probability the probability of an event A, conditional upon the occurrence of another event B is:

$P(A)=P(A|B)P(B)+P(A|B^{c})P(B^{c})$

Use this law to compute the probability of person having a positive result as follows:

$P(X)=P(X|A)P(A)+P(X|A^{c})P(A^{c})\\=(1\times0.01)+(0.005\times(1-0.01))\\=0.01+0.00495\\=0.01495$

The percentage of positive result is: 0.01495 × 100 = 1.495%.

Thus, the percentage of the population will give a positive test is 1.495%.

4 0

3 years ago