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dedylja [7]
3 years ago
10

What is the gcf and lcm of 35 and 56

Mathematics
1 answer:
anzhelika [568]3 years ago
8 0
What is the opposite of -3/4

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Which statement describes the inverse of m(x) = x2 – 17x?
stealth61 [152]

Answer:

The correct option is;

The \ domain \ restriction \ x \geq \dfrac{17}{2} \ results \ in \ m^{-1}(x) = \dfrac{17}{2} \pm \sqrt{x + \dfrac{289}{4} }}

Step-by-step explanation:

The given information is that m(x) = x² - 17·x

The above equation can be written in the form;

y = x² - 17·x

Therefore;

0 = x² - 17·x - y

From the general solution of a quadratic equation, 0 = a·x² + b·x + c we have;

x = \dfrac{-b\pm \sqrt{b^{2}-4\cdot a\cdot c}}{2\cdot a}

By comparison to the equation,0 = x² - 17·x - y, we have;

a = 1, b = -17, and c = -y

Substituting the values of a, b and c into the formula for the general solution of a quadratic equation, we have;

x = \dfrac{-(-17)\pm \sqrt{(-17)^{2}-4\times (1) \times (-y)}}{2\times (1)} = \dfrac{17\pm \sqrt{289+4\cdot y}}{2}

Which can be simplified as follows;

x =  \dfrac{17\pm \sqrt{289+4\cdot y}}{2}= \dfrac{17}{2} \pm \dfrac{1}{2}  \times \sqrt{289+4\cdot y}} = \dfrac{17}{2} \pm \sqrt{\dfrac{289}{4} +\dfrac{4\cdot y}{4} }}

And further simplified as follows;

x = \dfrac{17}{2} \pm \sqrt{\dfrac{289}{4} +y }} = \dfrac{17}{2} \pm \sqrt{y + \dfrac{289}{4} }}

Interchanging x and y in the function of the inverse, m⁻¹(x), we have;

m^{-1}(x) = \dfrac{17}{2} \pm \sqrt{x + \dfrac{289}{4} }}

We note that the maximum or minimum point of the function, m(x) = x² - 17·x found by differentiating the function and equating the result to zero, gives;

m'(x) = 2·x - 17 = 0

x = 17/2

Similarly, the second derivative is taken to determine if the given point is a maximum or minimum point as follows;

m''(x) = 2 > 0, therefore, the point is a minimum point on the graph

Therefore, as x increases past the minimum point of 17/2, m⁻¹(x) increases to give;

The \ domain \ restriction \ x \geq \dfrac{17}{2} \ results \ in \ m^{-1}(x) = \dfrac{17}{2} \pm \sqrt{x + \dfrac{289}{4} }} to increase m⁻¹(x) above the minimum.

8 0
3 years ago
What is the sum of three even consecutive integers is -72
Inga [223]

Answer:

-26,-24,-22

Step-by-step explanation:

<em><u>The correct question is</u></em>

The sum of three consecutive even integers is -72. what are the three numbers

Let

x ----> the first consecutive even integer

x+2 ----> the second consecutive even integer

x+4 ----> the third consecutive even integer

we know that

x+(x+2)+(x+4)=-72

solve for x

3x+6=-72\\3x=-78\\x=-26

so

x+2=-26+2=-24

x+4=-26+4=-22

therefore

the numbers are

-26,-24,-22

7 0
3 years ago
Evaluate t-u/v, when t=-1,u=-3 and v=1/2
mars1129 [50]

Answer:

5

Step-by-step explanation:

t-u/v

substitute (-1) - (-3)/(1/2)

divide     (-1) - (-6)

simplify   (-1) + 6

add         5

3 0
3 years ago
TELL ME IF YOU AGREE IF NOT WHAT SHOULD I CHANGE??! THX
docker41 [41]

Answer:

for my opinion, i think yo should try, i agree.

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
Miranda enlarged a picture twice as shown below, each time using a scale factor of 3.
lyudmila [28]

Answer:

The area of the second enlargement is 1,944 square inches

The area of the second enlargement is (3 squared) squared times the original area.

The ratio of the area of the first enlargement to the area of the original equals the square of the scale factor

Step-by-step explanation:

<u><em>Verify each statement</em></u>

1) The area of the first enlargement is 72 square inches.

The statement is false

Because

we know that

The original dimensions of the rectangle are

length 6 inches and width 4 inches

so

First enlargement

Multiply the original dimensions by a scale factor of 3

Length: 6(3)=18\ inches\\Width: 4(3)=12\ inches

The area of the first enlargement is

18(12)=216\ in^2

2) The area of the second enlargement is 1,944 square inches

The statement is true

Multiply the dimensions of the first enlargement by a scale factor of 3

Length: 18(3)=54\ inches\\Width: 12(3)=36\ inches

The area of the second enlargement is

54(36)=1,944\ in^2

3) The area of the second enlargement is (3 squared) squared times the original area.

The statement is true

Because

The original area is 24 square inches

[(3^2)]^2(24)=1,944\ in^2

4) The area of the second enlargement is 3 times the area of the first enlargement

The statement is false

Because

3(216)=648\ in^2

so

648\ in^2 \neq 1,944\ in^2

5) The ratio of the area of the first enlargement to the area of the original equals the square of the scale factor

The statement is true

Because

The square of the scale factor is 3^2=9

and the ratio is equal to

\frac{216}{24}=9

8 0
3 years ago
Read 2 more answers
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