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valentina_108 [34]
2 years ago
9

On Monday, a company stock closed at a price of $30.80 per share. On Tuesday, it increased by $1.20 per share. On Wednesday, it

fell by 6.25%. On Thursday, it fell by another 4%, and on Friday, it increased by 2.5%. What is the net change in the stock price from Monday to Friday? -$1.28
Mathematics
1 answer:
anygoal [31]2 years ago
7 0
If I did this correctly, the answer should be 2.72. Monday's stock price is given to you already, 30.80. To find Tuesday's, you'd add 1.20 to the already existing 30.80, that totals to 32. To find the number for Wednesday you would have to get the percentage and move the decimal so you can multiply it, it should end at .0625. You then get that number and multiply it by 32 because it was Tuesday's amount. From that you should get 2. You then subtract the 2 and the total for Wednesday is 30. You do the same for Thursday, you get the already existing number, 30, and multiply it by .04. That should end in 1.2. You then subtract that 1.2 and you should get 28.8 as your answer for Thursday. For Friday, the steps repeat. You take the 28.8 and multiply it by .025. That should equal to .72. You now subtract that .72 from Thursday's amount and should be left with 28.08 for Friday. Now that all the numbers are known, take the numbers for Monday and for Friday and then subtract them. (30.80-28.08) It should equal to 2.72.
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Answer: 27434

Step-by-step explanation:

Given : Total number of vials = 56

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The number of combinations of m thing r things at a time is given by :-

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^{13}C_2\cdot ^{43}C_{1}+^{13}C_{1}\cdot ^{43}C_{2}+^{13}C_0\cdot ^{43}C_{3}\\\\=\dfrac{13!}{2!(13-2)!}\cdot\dfrac{43!}{1!(42)!}+\dfrac{13!}{1!(12)!}\cdot\dfrac{43!}{2!(41)!}+\dfrac{13!}{0!(13)!}\cdot\dfrac{43!}{3!(40)!}\\\\=\dfrac{13\times12\times11!}{2\times11!}\cdot (43)+(13)\cdot\dfrac{43\times42\times41!}{2\times41!}+(1)\dfrac{43\times42\times41\times40!}{6\times40!}\\\\=3354+11739+12341=27434

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Step-by-step explanation:

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