Answer:
The frequency of homozygous recessive offspring in a cross between two heterozygotes is 25%.
Explanation:
Since the alleles are of two types, that is dominant and recessive alleles. An heterozygous parent will have both alleles.
So, we can represent our dominant allele with G and the recessive allele with g.
Then, the two heterozygous parents will have Gg genes.
These alleles will be segregated into their singleness. the first parent will therefore have G and g and the second parent will also have G and g
Crossing these alleles using punnet's square, we the have the following genotypic ratio of the progenies: 1GG: 2Gg: 1gg
Therefore, the 1gg is the only heterozygous offspring out of the expected four offsprings. This made the frequency to be 1/4 X 100 = 25%.
Answer: D. The N-formyl group on methionine prevents fMet from entering interior positions in a polypeptide.
Answer: Glucose
Explanation: Photosynthesis is a set of chemical reactions that uses energy from the sun and carbon dioxide to produce sugar and oxygen. The sugar provides plants with energy to grow.
Answer:
(E)
Explanation:
The binding of glucose to liver phosphorylase a shifts the equilibrium from the active form to the inactive form.