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Sliva [168]
2 years ago
14

You need 368cm of tape for a project, how many decimeters is this?

Mathematics
2 answers:
son4ous [18]2 years ago
8 0
368 cm of tape is equal to is 36.8 dm
ki77a [65]2 years ago
6 0

..............36.8 dm

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Help meee plssss!!!!!
lakkis [162]

Circumference of circle is 62.8 inches.

Step-by-step explanation:

Using Formula

Circumference of circle = 2 π r

Substitute the values

Circumference of circle = 2 × 3.14 × 10 inches.

multiply the numbers

Circumference of circle = 62.8 inches

Hence, the circumference of circle is 62.8 inches.

8 0
3 years ago
What are three terms in the sequence 4096, 1024, 256, 64
mash [69]

If you mean 3 more terms in the sequence they could be

64, 32, 16, 8 ...

If you mean any 3 terms then 4096 1024 and 256 qualify.

6 0
3 years ago
Read 2 more answers
Help on geometry please (answer #5)
jekas [21]

it would be a, b, and c because if you look at the question and the answers, 3 of the four answers match the 3 of the 4 coordinates

6 0
3 years ago
If x = -5, which inequality is true?
stealth61 [152]

Answer:

A

Step-by-step explanation:

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8 0
2 years ago
A survey was conducted that asked 1003 people how many books they had read in the past year. Results indicated that x overbar eq
Sergio [31]

Answer:

The 99% confidence interval would be given (11.448;14.152).

Step-by-step explanation:

1) Important concepts and notation

A confidence interval for a mean "gives us a range of plausible values for the population mean. If a confidence interval does not include a particular value, we can say that it is not likely that the particular value is the true population mean"

s=16.6 represent the sample deviation

\bar X=12.8 represent the sample mean

n =1003 is the sample size selected

Confidence =99% or 0.99

\alpha=1-0.99=0.01 represent the significance level.

2) Solution to the problem

The confidence interval for the mean would be given by this formula

\bar X \pm z_{\alpha/2} \frac{s}{\sqrt{n}}

We can use a z quantile instead of t since the sample size is large enough.

For the 99% confidence interval the value of \alpha=1-0.99=0.01 and \alpha/2=0.005, with that value we can find the quantile required for the interval in the normal standard distribution.

z_{\alpha/2}=2.58

And replacing into the confidence interval formula we got:

12.8 - 2.58 \frac{16.6}{\sqrt{1003}}=11.448

12.8 + 2.58 \frac{16.6}{\sqrt{1003}} =14.152

And the 99% confidence interval would be given (11.448;14.152).

We are confident that about 11 to 14 are the number of books that the people had read on the last year on average, at 1% of significance.

3 0
3 years ago
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