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Arlecino [84]
2 years ago
13

Christopher's construction company bought 5 bags of gravel they used 3 2/5 bags on m r.pain's driveway how many bags do they hav

e left?
Mathematics
1 answer:
lyudmila [28]2 years ago
5 0
1 3/5 because 5 - 3(2/5) = 1 3/5
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I have no idea how to do this, it is due in two days. Hopefully someone sees this before then.
elena-14-01-66 [18.8K]

Hello,

m\ \widehat{ABC}=x\\m\ \widehat{BAC}=2*x\\\\So:\\ x+2x=90^o\\x=30^o\\

cos(30^o)=\dfrac{\sqrt{3} }{2} \\

In the triangle ABC,

cos(30^o)=\frac{BC}{BA} \\\\BA=\dfrac{cos(30^o)}{BC} \\\\BA=\frac{\dfrac{\sqrt{3} }{2} }{24} =16*\sqrt{3} \\\\

sin(30^o)=\dfrac{1 }{2} =\dfrac{AC}{AB} \\\\AC=\dfrac{1}{2} *16\sqrt{3} =8\sqrt{3}

In the triangle ACB,

cos(30^o)=\dfrac{AC}{AL} \\\\AL=\dfrac{8\sqrt{3} *2}{\sqrt{3} } =16\\

6 0
3 years ago
What is the congruence method you will use to show that the triangles are congruent?
kozerog [31]
The answer would be SSS or Side-Side-Side.
4 0
2 years ago
Read 2 more answers
How to know if a function is periodic without graphing it ?
zhenek [66]
A function f(t) is periodic if there is some constant k such that f(t+k)=f(k) for all t in the domain of f(t). Then k is the "period" of f(t).

Example:

If f(x)=\sin x, then we have \sin(x+2\pi)=\sin x\cos2\pi+\cos x\sin2\pi=\sin x, and so \sin x is periodic with period 2\pi.

It gets a bit more complicated for a function like yours. We're looking for k such that

\pi\sin\left(\dfrac\pi2(t+k)\right)+1.8\cos\left(\dfrac{7\pi}5(t+k)\right)=\pi\sin\dfrac{\pi t}2+1.8\cos\dfrac{7\pi t}5

Expanding on the left, you have

\pi\sin\dfrac{\pi t}2\cos\dfrac{k\pi}2+\pi\cos\dfrac{\pi t}2\sin\dfrac{k\pi}2

and

1.8\cos\dfrac{7\pi t}5\cos\dfrac{7k\pi}5-1.8\sin\dfrac{7\pi t}5\sin\dfrac{7k\pi}5

It follows that the following must be satisfied:

\begin{cases}\cos\dfrac{k\pi}2=1\\\\\sin\dfrac{k\pi}2=0\\\\\cos\dfrac{7k\pi}5=1\\\\\sin\dfrac{7k\pi}5=0\end{cases}

The first two equations are satisfied whenever k\in\{0,\pm4,\pm8,\ldots\}, or more generally, when k=4n and n\in\mathbb Z (i.e. any multiple of 4).

The second two are satisfied whenever k\in\left\{0,\pm\dfrac{10}7,\pm\dfrac{20}7,\ldots\right\}, and more generally when k=\dfrac{10n}7 with n\in\mathbb Z (any multiple of 10/7).

It then follows that all four equations will be satisfied whenever the two sets above intersect. This happens when k is any common multiple of 4 and 10/7. The least positive one would be 20, which means the period for your function is 20.

Let's verify:

\sin\left(\dfrac\pi2(t+20)\right)=\sin\dfrac{\pi t}2\underbrace{\cos10\pi}_1+\cos\dfrac{\pi t}2\underbrace{\sin10\pi}_0=\sin\dfrac{\pi t}2

\cos\left(\dfrac{7\pi}5(t+20)\right)=\cos\dfrac{7\pi t}5\underbrace{\cos28\pi}_1-\sin\dfrac{7\pi t}5\underbrace{\sin28\pi}_0=\cos\dfrac{7\pi t}5

More generally, it can be shown that

f(t)=\displaystyle\sum_{i=1}^n(a_i\sin(b_it)+c_i\cos(d_it))

is periodic with period \mbox{lcm}(b_1,\ldots,b_n,d_1,\ldots,d_n).
4 0
3 years ago
ABCD is a rectangle. What is the value of x? A 56 m B 65 m Xm C​
nalin [4]

Answer:

ABCD is a rectangle. What is the value of x? A 56 m B 65 m Xm C

3 0
3 years ago
HOOK is a word that has horizontal line symmetry since it is made up of letters that each have horizontal line symmetry. Can you
storchak [24]

Another word that has horizontal line symmetry is "book" and it is possible to form words with vertical line symmetry.

<h3>What is horizontal line symmetry in letters?</h3>

This implies that by dividing the letter in half using a horizontal line both sides would be the same. Lettters with horizontal line symmetry include:

  • H
  • K
  • O
  • E
  • B
  • C

<h3>What are some words with these symmetry?</h3>
  • Hood
  • Book
  • Cook
  • Bee

<h3>Are words with vertical line symmetry possible?</h3>

Yes, they are because there are many letters that have this symmetry such as V, T, A, O, M, I, H. For example you can create the words:

  • Hi
  • Mum
  • Hit

Learn more about letters in: brainly.com/question/10361926

6 0
2 years ago
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