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a_sh-v [17]
3 years ago
6

Which measurement is equivalent to 47 mL?

Mathematics
1 answer:
Gennadij [26K]3 years ago
8 0
We have that
47 ml

we know that
1 lt------------> 1000 ml
X lt -------------> 47 ml
X=47/1000--------> x=0.047 lt

the answer is the option
D: 0.047 L
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Suresh has 4 coupon books, each with 6 coupons. He keeps 13 of the coupons and gives the rest away. Fifty percent of those he ke
Dafna11 [192]

Answer:

the answer is 6.5

Step-by-step explanation:

4x6=24 24-13=11    so Suresh gave 11 coupons away

13 divided by 2 = 6.5

6 0
3 years ago
Sin(2x-pi/2)=sin pi/3
svet-max [94.6K]
This is the answer for your question!

8 0
3 years ago
If
Leno4ka [110]

Answer:

\frac{s^2-25}{(s^2+25)^2}

Step-by-step explanation:

Let's use the definition of the Laplace transform and the identity given:\mathcal{L}[t \cos 5t]=(-1)F'(s) with F(s)=\mathcal{L}[\cos 5t].

Now, F(s)=\int_0 ^{+ \infty}e^{-st}\cos(5t) dt. Using integration by parts with u=e^(-st) and dv=cos(5t), we obtain that F(s)=\frac{1}{5}\sin(5t)e^{-st} |_{0}^{+\infty}+\frac{s}{5}\int_0 ^{+ \infty}e^{-st}\sin(5t) dt=\int_0 ^{+ \infty}e^{-st}\sin(5t) dt.

Using integration by parts again with u=e^(-st) and dv=sin(5t), we obtain that

F(s)=\frac{s}{5}(\frac{-1}{5}\cos(5t)e^{-st} |_{0}^{+\infty}-\frac{s}{5}\int_0 ^{+ \infty}e^{-st}\sin(5t) dt)=\frac{s}{5}(\frac{1}{5}-\frac{s}{5}\int_0^{+ \infty}e^{-st}\sin(5t) dt)=\frac{s}{5}-\frac{s^2}{25}F(s).

Solving for F(s) on the last equation, F(s)=\frac{s}{s^2+25}, then the Laplace transform we were searching is -F'(s)=\frac{s^2-25}{(s^2+25)^2}

3 0
3 years ago
Can someone help me and you need to round to nearest whole number
andrew11 [14]

Answer:

look at the picture i have sent

5 0
3 years ago
Help please thank you if u do!
dmitriy555 [2]
I think d but i might be wrong :( sorry
7 0
3 years ago
Read 2 more answers
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